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natka813 [3]
3 years ago
15

4 newtons, 4 amps, 4 joules, 4 watts, 4 ohms, 4 volts what does I=

Physics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

I = 4 amperes

Explanation:

Newton is the unit of force. Hence  4 newton is not the current “I”

Joules is the unit of  energy and hence it do not signify current I

Watt is the unit of power i.e the rate of transfer of energy.  

Ohm is the unit of resistance produces thereby obstructing the flow of current

And Volts is the unit of voltage or potential difference between two ends of an electric circuit. Thus, it is also does not signifies current.

Thus, I = 4 amperes

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When are magnets attracted and when are they repelled.
vova2212 [387]
Magnets are attracted when each of the different sides, most commonly known as "North" and "South", are facing each other. They repel when North and North, or South and South are facing each other.
3 0
4 years ago
Fiber optics are an important part of our modern internet. In these fibers, two different glasses are used to confine the light
motikmotik

Answer:

n_cladding = 1.4764

Explanation:

We are told that θ_max = 5 °

Thus;

θ_max + θ_c = 90°

θ_c = 90° - θ_max

θ_c = 90° - 5°

θ_c = 85°

Now, critical angle is given by;

θ_c = sin^(-1) (n_cladding/n_core)

sin θ_c = (n_cladding/n_core)

n_cladding = (n_core) × sin θ_c

Plugging in the relevant values, we have;

n_cladding = 1.482 × sin 85

n_cladding = 1.4764

7 0
3 years ago
In a low-density cloud, the internal pressure is much too low to support the weight, so the cloud must __________, eventually pr
andrey2020 [161]

The answer to this question is flatten

so the cloud must <u>flatten</u> eventually producing the galaxy s disk.

3 0
4 years ago
A projectile is fired from the origin (at y = 0 m) as shown in the diagram. The initial velocity
Viktor [21]

Answer:

-26 m/s.

Explanation:

Hello,

In this case, since the vertical initial velocity is 26 m/s and the vertical final velocity is 0 m/s at P, we compute the time to reach P:

t=\frac{0m/s-26m/s}{-9.8m/s^2} =2.65s

With which we compute the maximum height:

y=26m/s*2.65s-\frac{1}{2}*9.8m/s^2*(2.65s)^2 \\\\y=34.5m

Therefore, the final velocity until the floor, assuming P as the starting point (Voy=0m/s), turns out:

v_f=\sqrt{0m/s-(-9.8m/s^2)*2*34.5m}\\ \\v_f=-26m/s

Which is clearly negative since it the projectile is moving downwards the starting point.

Regards.

3 0
4 years ago
An aircraft maintenance technician walks past a tall hangar door that acts like a single slit for sound entering the hangar. Out
Sphinxa [80]

Answer:

The first minimum would be observed at 41.57°

Explanation:

v = 340m/s = speed of sound

f = 610Hz

d = 0.840m

λ = ?

Mλ = wsinθ

m = mth order minima

λ = wavelength incident on the single slit

θ = angular position of the mth minima

But, λ = v / f

λ = 340 / 610 = 0.557m

θ = sin⁻(mλ/d)

θ = sin⁻ [(1 * 0.557) / 0.840]

θ = sin⁻ 0.6635

θ = 41.57°

The first minimum would be observed at 41.57°

4 0
4 years ago
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