Point charges q1=+2.00μC and q2=−2.00μC are placed at adjacent corners of a square for which the length of each side is 5.00 cm.?
Point a is at the center of the square, and point b is at the empty corner closest to q2. Take the electric potential to be zero at a distance far from both charges.
(a) What is the electric potential at point a due to q1 and q2?
(b) What is the electric potential at point b?
(c) A point charge q3 = -6.00 μC moves from point a to point b. How much work is done on q3 by the electric forces exerted by q1 and q2?
Answer:
a) the potential is zero at the center .
Explanation:
a) since the two equal-magnitude and oppositely charged particles are equidistant
b)(b) Electric potential at point b, v = Σ kQ/r
r = 5cm = 0.05m
k = 8.99*10^9 N·m²/C²
Q = -2 microcoulomb
v= (8.99*10^9) * (2*10^-6) * (1/√2m - 1) / 0.0500m
v = -105 324 V
c)workdone = charge * potential
work = -6.00µC * -105324V
work = 0.632 J
Answer:
Gamma radiation
Explanation:
There are three types of ionizing radiation:
- Alpha radiation: it consists of alpha particles, which are nuclei of helium (so, they contain 2 protons and 2 neutron) --> therefore, they have a net charge of +2 (given by the positive charge of the two electrons)
- Beta radiation: it consists of electron (in case of beta-minus radiation) or positrons (in case of beta-plus radiation). Therefore, in both cases the radiation is electrically charged: charge -e for the electrons, charge +e for the positrons
- Gamma radiation: it consists of high-energy photons. Since photons are electrically neutral, gamma radiation has no electric charge associated with it.
Answer:
Total time spend = 48.18 hours (Approx)
Explanation:
Given:
Total distance = 5,300 km
Average speed = 110 km / h
Find:
Total time spend
Computation:
Time = Distance / speed
Total time spend = Total distance / Average speed
Total time spend = 5,300 / 110
Total time spend = 48.18 hours (Approx)
The amount of heat needed to increase the temperature of a 1-kilogram substance by 1°C is known as the specific heat of the substance.
the formula for specific heat of a substance is given as
c = Q/(m ΔT)
where Q = Heat required to change the temperature by 1°C
m = mass of the substance
ΔT = change in temperature.
the units of specific heat is given as Joules/(kilogram °C)
Answer:
material work function is 0.956 eV
Explanation:
given data
red wavelength 651 nm
green wavelength 521 nm
photo electrons = 1.50 × maximum kinetic energy
to find out
material work function
solution
we know by Einstein photo electric equation that is
for red light
h ( c / λr ) = Ф + kinetic energy
for green light
h ( c / λg ) = Ф + 1.50 × kinetic energy
now from both equation put kinetic energy from red to green
h ( c / λg ) = Ф + 1.50 × (h ( c / λr ) - Ф)
Ф =( hc / 0.50) × ( 1.50/ λr - 1/ λg)
put all value
Ф =( 6.63 ×
(3 ×
) / 0.50) × ( 1.50/ λr - 1/ λg)
Ф =( 6.63 × (3 × ) / 0.50 ) × ( 1.50/ 651×
- 1/ 521 ×)
Ф = 1.5305 ×
J × ( 1ev / 1.6 × J )
Ф = 0.956 eV
material work function is 0.956 eV
