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Goshia [24]
3 years ago
11

College students living off-campus frequently consume large amounts of ramen noodles and boxed macaroni and cheese. When they fi

nish school and start careers, their consumption of both goods frequently declines. This suggests that ramen noodles and boxed macaroni and cheese are:
Physics
1 answer:
tigry1 [53]3 years ago
4 0

Answer:

Ramen Noodles and boxed Macaroni and Cheese are COMPLEMENTARY Goods

Explanation:

Complementary Goods are goods that are demanded jointly (together) to satisfy a particular want.

Ramen Noodles, Boxed Macaroni, Cheese are demanded together by off campus college students. So, they are complementary goods.

Also, their demand are directly related - demand of one good increases, demand of other good increases & demand of one good decreases , demand of other good decreases ; because they are demanded together.

After school end , consumption of all goods declining together - is also their characteristic pointing towards them being Complementary Goods .

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You drop a ball from a height of 2.0 m, and it bounces back to a height of 1.5 m. (a) what fraction of its initial energy is los
Scilla [17]

a) At a position of 2.0m, the Initial energy is all made up of the potential energy=m*g*hi<span>
and meanwhile at 1.5 all its energy is also potential energy=m*g*hf 

The percentage of energy remaining is E=m*g*hi/m*g*hf x 100 

and since mass and gravity are constant so it leaves us with just E=hi/hf 
which 1.5/2.0 x100= 75% so we see that we lost 25% of the energy or 0.25 in fraction 

b) Here use the equation vf^2=vi^2+2gd 

<span>where g is gravity, vf is the final velocity and vi is the initial velocity while d is the distance travelled

so in here we are looking for the vi so let us isolate that variable 
we know that at maximum height or peak, the velocity is 0 so vf is 0 

therefore,</span></span>

vi =sqrt(-2gd) <span>
vi =sqrt(-2x-9.81x1.5) </span>
<span>vi =5.4 m/s

<span>c) The energy was converted to heat due to friction with the air and the ground.</span></span>

6 0
3 years ago
A woman using a compass and a map walks 132 east of north for 6 km
ANEK [815]
If she walks 132 and 6 you do 132 x 6 = 792
7 0
3 years ago
Read 2 more answers
You paddle a conoe with a force of 325 N. You and the canoe have a combined mass of 250 kg. What is the acceleration of the cano
Brums [2.3K]

f = ma

Rearranging it, we get;

a =  \frac{f}{m}
Where a is the acceleration, f is the force, and m is the mass

a =  \frac{325}{250}
a = 1.3 \frac{m}{ {s}^{2} }

7 0
3 years ago
A baseball pitcher throws a ball at 90.0 mi/h in the horizontal direction. How far does the ball fall vertically by the time it
Lisa [10]

Answer:

Vertical distance=  3.3803ft

Explanation:

First with the speed of the ball and the distance traveled horizontally we can determine the flight time to reach the plate:

Velocity= (90 mi/h) × (1 mile/5280ft) = 475200ft/h

Distance= Velocity × time⇒ time= 60.5ft / (475200ft/h) = 0.00012731h

time=  0.00012731h × (3600s/h)= 0.458316s

With this time we can determine the distance traveled vertically taking into account that its initial vertical velocity is zero and its acceleration is that of gravity, 9.81m/s²:

Vertical distance= (1/2) × 9.81 (m/s²) × (0.458316s)²=1.0303m

Vertical distance= 1.0303m × (1ft/0.3048m) = 3.3803ft

This is the vertical distance traveled by the ball from the time it is thrown by the pitcher until it reaches the plate, regardless of air resistance.

3 0
3 years ago
A long point-object, mass = 1.0 kg, moves in a circular path at a radial distance = 0.5 m from the axis of rotation. What is the
Vinvika [58]

Answer:0.25\ kg-m^2

Explanation:

Given

mass of Point object m=1 kg

Distance r=0.5 m

Since mass is moving in circular path therefore every time mass is at distance of r from center .

Also Moment of Inertia tells about  the distribution of mass over the given region with respect to center of mass.

Therefore I=mr^2

I=1\times 0.5^2

I=0.25\ kg-m^2

5 0
3 years ago
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