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bixtya [17]
3 years ago
13

Rotation is the spin of a body on its axis. Revolution is the movement of one body around another in an ellipse-shaped path call

ed an orbit. Earth rotates on its axis and revolves around the Sun. The moon rotates on its axis and revolves around Earth.
Chemistry
1 answer:
ra1l [238]3 years ago
4 0

Answer:

Rotation is the circular movement of an objector planet around a center of rotation. The 3D objects like earth, moon and other planets always rotate around an imaginary line which is called the  rotation axis. If the axis passes through the body’s center of mass, the body is said to rotate upon itself or spin.

Revolution is referred to as an orbital revolution. It happens when one body moves around another, while rotation is used to mean the movement around the axis like Moon revolving around the Earth and  Earth revolving around the Sun.

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There are 207405.111 grams in that many pounds.
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In an atomic model that includes a nucleus, positive charge is
olganol [36]
<span>Because protons are positively charged and neutrons have no charge then it is safe to say that such an atomic model would have the positive charge concentrated in the center of an atom (option d).</span>
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3 years ago
You must answer all questions to get credit for this assignment. Use the notes above and/or the textbook to help you find the an
Allisa [31]

Explanation:

(1).  It is known that in a reaction equation, reactants are placed or written on left hand side and products are written on the right hand side.

For example, N_{2} + 3H_{2} \rightarrow 2NH_{3}

Hence, in a reaction equation you start with the reactants and end up with the products.

(2).  The number of atoms in a reaction will remain the same because according to the law of conservation of mass, mass of reactants will be equal to the mass of products.

Therefore, number of atoms on the reactant side will be equal to the number of atoms on product side.

7 0
3 years ago
Be sure to answer all parts. Write the equations representing the following processes. In each case, be sure to indicate the phy
barxatty [35]

Answer:

1.S^{-}(g)+e^{-} \rightarrow S^{2-}(g)

2.Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}

3.The electron affinity of  Mg^{2+} is zero.

4.O^{2-}(g) \rightarrow O^{-}(g)+e^{-}

Explanation:

1.

<u>Electron affinity:</u>

It is defined as the amount of energy change when an electron is added to atom in the gaseous phase.

The electron affinity of S^{-} is as follows.

S^{-}(g)+e^{-} \rightarrow S^{2-}(g)

2.

<u>Ionization energy</u>:

Amount of energy required to removal of an electron from an isolated gaseous atom.

The third ionization energy of Titanium is as follows.

Ti^{2+}(g) \rightarrow Ti^{3+}(g) \,\, IE = 2652.5\,kJ.mol^{-1}

3.

The electronic configuration of Mg: 1s^{2}2s^{2}2p^{6}3s^{2}

By the removal of two electrons from a magnesium element we get Mg^{2+} ion.

Mg^{2+} has inert gas configuration i.e,1s^{2}2s^{2}2p^{6}

Hence, it does not require more electrons to get stability.

Therefore,the electron affinity of  Mg^{2+} is zero.

4.

The ionization energy of O^{2-} is follows.

O^{2-}(g) \rightarrow O^{-}(g)+e^{-}

3 0
3 years ago
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