Cold freshwater<span> is </span>denser<span> than </span>warm seawater<span>, because of the salinity and temperature variations. Cold water would have less salt since the solubility of the salt is lower as compared to warm water. Hope this answers the question. Have a nice day.</span>
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We can point to the invention of the wheel . The wheel invention made possible the production of hundreds of complex machinery.
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Answer:
Explanation:
According to given:
- molecular mass of glycerin,
- molecular mass of water,
- ∵Density of water is
- ∴mass of water in 316 mL,
- mass of glycerin,
- pressure of mixture,
- temperature of mixture,
<em>Upon the formation of solution the vapour pressure will be reduced since we have one component of solution as non-volatile.</em>
<u>moles of water in the given quantity:</u>
<u>moles of glycerin in the given quantity:</u>
<u>Now the mole fraction of water:</u>
<em>Since glycerin is non-volatile in nature so the vapor pressure of the resulting solution will be due to water only.</em>
Answer:
Since F = G * m1 * m2 / r^2
F = 6.67 * 19E-11 * 2.79 * 9.47 * 10E23 / (1.2 * 10^7)^2
F = 126 * 10E-2 N = 1.22 N
Answer:
*The same balloon put into the freezer would be smaller and shriveled.
* The volume decreases as the temperature decreases.
* using a hypothetical starting volume of 2 liters in the balloon at 42 degrees Celsius, we can use the equation V1/T1 =V2/T2
V2= 1.54 liters which proves when temperature decreases , volume decreases as well.
Explanation:
The volume increases as the temperature increases, and volume decreases as the temperature decreases.
using a hypothetical starting volume of 2 liters in the balloon at 42 degrees Celsius, we can use the equation V1/T1 =V2/T2
Change Celsius to kelvin by adding 273.
2 liters/ 315 K = V2/243 K
Cross multiply and then divide by 315 to find V2
2 liters x 243 K / 315 K = V2
The Kelvin cancels itself out.
486 liters /315=V2
V2= 1.54 liters.
This proves that when the temperature decreases , so does the volume.
