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olga_2 [115]
3 years ago
14

Please help answer the question in the screenshot. it's multiple choice..

Physics
1 answer:
Talja [164]3 years ago
7 0

Answer:

Since F = G * m1 * m2 / r^2

F = 6.67 * 19E-11 * 2.79 * 9.47 * 10E23 / (1.2 * 10^7)^2

F = 126 * 10E-2 N  = 1.22 N

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It is because it is a unit of Power(which is a derived quantity)

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When you use the front brakes on your bicycle, why does your body want to rotate over the front wheel
stiv31 [10]

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pshichka [43]

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3 0
3 years ago
Find a numerical value for ρearth, the average density of the earth in kilograms per cubic meter. use 6378km for the radius of t
Andre45 [30]

Answer:

5501 kg/m^3

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The value of g at the Earth's surface is

g=\frac{GM}{R^2}=9.70 m/s^2

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R=6378km = 6.378 \cdot 10^6 m is the Earth's radius

Solving the formula for M, we find the value of the Earth's mass:

M=\frac{gR^2}{G}=\frac{(9.81 m/s^2)(6.378\cdot 10^6 m)^2}{6.67\cdot 10^{-11}}=5.98\cdot 10^{24}kg

The Earth's volume is (approximating the Earth to a perfect sphere)

V=\frac{4}{3}\pi r^3 = \frac{4}{3}\pi (6.378\cdot 10^6 m)^3=1.087\cdot 10^{21} m^3

So, the average density of the Earth is

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4 0
4 years ago
Read 2 more answers
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