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2 years ago

If you fall from a building onto a net which extends the time of impact by 10 times, what happens to the force you experience?

Physics

1 answer:

zubka84 [21]2 years ago

6 0

Answer:

A larger impulse. A 1-kg ball has twice as much speed as a 10-kg ball.

Explanation:

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The Eiffel tower in Paris is 300 meters tall on a cold day (T = -24 degrees Celsius), what is its height on a hot day when the t

Varvara68 [4.7K]

Answer:

Length of Eiffel tower, when the temperature is 35 degrees = 300.21 m

Explanation:

Thermal expansion is given by the expression

$\Delta L=L\alpha \Delta T \\$

Here length of Eiffel tower, L = 300 m

Coefficient of thermal expansion, α = 0.000012 per degree Celsius

Change in temperature, = 35 - (-24) = 59degrees Celsius

Substituting

$\Delta L=L\alpha \Delta T= 300\times 0.000012\times 59=0.2124m \\$

Length of Eiffel tower, when the temperature is 35 degrees = 300 + 0.2124 = 300.21 m

3 0

2 years ago

• Usain Bolt can run at 10 m/s. If he runs for about 20 seconds, how far around the race track did he go?

yanalaym [24]

Answer:

200metters

Explanation:

because in one second hes going 10 metter in 20 second he will go 20×10=200

4 0

2 years ago

S A voltage ΔV is applied to a series configuration of n resistors, each of resistance R. The circuit components are reconnected

Flura [38]

The power of is series combination is Vn^2 times that of a parallel combination.

For series combination :

Req = R + R + R + ............... n times = nR

I = Δv/nr

Power = (Δv/nr)^2 × nr = Δv^2/nr

For parallel combination

1/req = 1/R + 1/R + 1/R +................(n times) = n/R

Req = R/n

Power = Δv/(R/n) = nΔv^2/R

Ratio = Δv^2/nr/n·Δv^2/R = 1/n^2

Hence, power of is series combination is Vn^2 times that of a parallel.

Learn more about parallel combination here:

brainly.com/question/12400458

#SPJ4

3 0

1 year ago

You push a 1.30 kg physics book 2.80 m along a horizontal tabletop with a horizontal push of 1.55 N while the opposing force of

Rzqust [24]

Answer:

Explanation:

Step one:

given data

mass m= 1.3kg

distance moved s= 2.8m

opposing frictional force= 0.34N

assume g= 9.81m/s^2

we know that work done= force *distance moved

1. work done to push the book= 1.55*2.8=4.34J

2. Work against friction = force of friction x distance

= 0.34*2.8=0.952J

Step two:

the work done on the book is the net work, which is

Network done= work done to push the book- Work against friction

Network done= 4.32-0.952=3.36J

<u>Therefore the work of the 1.55N 3.36J</u>

4 0

2 years ago

1. The asthenosphere and lithosphere are parts of Earth's

miss Akunina [59]

did you tried first if you did I can help

7 0

2 years ago