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Shalnov [3]
4 years ago
10

Work is done on a locked door that remains closed while you try to pull it open. True False.

Physics
1 answer:
dsp734 years ago
8 0

Answer:False

Explanation:

Work is being done on a body when it causes displacement of body on the application of force

Work\ done=Force\times displacement

When we pull the door by a force it causes zero displacements of the door. So we can say that work done on it is zero.

Thus the above-given statement is false  

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The pressure of an ideal gas is 4 atm. If the only change is to increase the temperature by a factor of 4, what will be the new
Tatiana [17]

Answer:

The new pressure is 4 times of the initial pressure.

Explanation:

Given that,

The pressure of an ideal gas is 4 atm.

We need to find the change in the pressure of the gas if the temperature by a factor of 4.

We know that,

PV = nKT ....(1)

P = pressure, V = volume, T = temperature

Let P' is the new pressure of the gas. So,

P'V= nK(4T) ......(2)

Dividing equation (1) and (2) we get :

\dfrac{P}{P'}=\dfrac{T}{4T}\\\\\dfrac{P}{P'}=\dfrac{1}{4}\\\\P'=4P

It means that the new pressure is 4 times of the initial pressure.

5 0
4 years ago
The blank of blank is what creates electricity
sveticcg [70]

Answer:

blank plus water is produ-ed in a tunnel and generate the electricity

6 0
3 years ago
A toy car accelerates at a constant rate from rest to a speed of 4 m/s in a time of 0.55 s. What was the magnitude of the accele
Korvikt [17]
  • initial velocity=u=0m/s
  • Final velocity=v=4m/s
  • Time=t=0.5s

\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}

\\ \sf\longmapsto Acceleration=\dfrac{4-0}{0.5}

\\ \sf\longmapsto Acceleration=\dfrac{4}{0.5}

\\ \sf\longmapsto Acceleration=8m/s^2

3 0
3 years ago
A 81 cm long brass rod has a diameter of 3 mm. The temperature of one end is 50 degrees higher than the other end. How much heat
harina [27]

Answer:

5.14 J

Explanation:

l = 81 cm = 0.81 m

diameter = 3 mm

Radius, r = 1.5 mm = 1.5 x 10^-3 m

Change in temperature, T2 - T1 = 50 degree

t = 1.8 minutes = 1.8 x 60 = 108 s

k = 109 W/mk

Heat transfer = K A (T2 - T1) t / l

H = 109 x 3.14 x 1.5 x 10^-3 x 1.5 x 10^-3 x 50 x 108 / 0.81

H = 5.14 J

3 0
3 years ago
A very long, straight wire has charge per unit length 3.50×10^−10 C/m . At what distance from the wire is the electricfield magn
Dafna11 [192]

Answer:

r= 2.17 m

Explanation:

Conceptual Analysis:

The electric field at a distance r from a charge line of infinite length and constant charge per unit length is calculated as follows:

E= 2k*(λ/r) Formula (1)

Where:

E: electric field .( N/C)

k: Coulomb electric constant. (N*m²/C²)

λ: linear charge density. (C/m)

r : distance from the charge line to the surface where E calculates (m)

Known data

E= 2.9  N/C

λ = 3.5*10⁻¹⁰ C/m

k= 8.99 *10⁹ N*m²/C²

Problem development

We replace data in the formula (1):

E= 2*k*(λ/r)

2.9= 2*8.99 *10⁹*(3.5*10⁻¹⁰/r)

r =( 2*8.99 *10⁹*3.5*10⁻¹⁰) / (2.9)

r= 2.17 m

5 0
3 years ago
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