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Tom [10]
2 years ago
13

Raven, Omega, and Red Knight are trying to earn battle stars in physics class by solving energy problems. All three have the sam

e mass. Raven runs up the stairs in 4 seconds, Omega skips up the stairs in 6 seconds, and Red Knight walks up the stairs in 15 seconds. Which skin has the greatest power?
a) red knight

b) they're all the same

c)raven

d)omega​
Physics
1 answer:
AlexFokin [52]2 years ago
5 0
Is this some kind of fortntie questions?
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Mass (kg)
Tju [1.3M]

Mass.

Because mass doesn't depend on weight but weight depends on mass.

8 0
3 years ago
Read 2 more answers
Vertical Motion
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3 0
3 years ago
The maximum height a typical person can jump is about 60cm (0.6m). By how much does the gravitational potential energy increase
sasho [114]

The gravitational potential energy will increase by 423.36 J

<h3>How to determine the potential energy at ground level</h3>
  • Mass (m) = 72 kg
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height (h) = 0 m
  • Potential energy at ground level (PE₁) =?

PE = mgh

PE₁ = 72 × 9.8 × 0

PE₁ = 0 J

<h3>How to determine the potential energy at 60 cm (0.6 m)</h3>
  • Mass (m) = 72 kg
  • Acceleration due to gravity (g) = 9.8 m/s²
  • Height (h) = 0.6 m
  • Potential energy at 60 cm (0.6 m) (PE₂) =?

PE = mgh

PE₂ = 72 × 9.8 × 0.6

PE₂= 423.36 J

<h3>How to determine the change in potential energy </h3>
  • Potential energy at ground level (PE₁) = 0 J
  • Potential energy at 60 cm (0.6 m) (PE₂) = 423.36 J
  • Change in potential energy =?

Change in potential energy = PE₂ - PE₁

Change in potential energy = 423.36 - 0

Change in potential energy = 423.36 J

Learn more about energy:

brainly.com/question/10703928

#SPJ1

8 0
1 year ago
A 4.40-kilogram hoop starts from rest at a height 1.70 m above the base of an inclined plane and rolls down under the influence
Anestetic [448]

Answer:

The linear velocity is  v=4.08m/s

Explanation:

According to the law of conservation of energy

   The potential energy possessed by the  hoop at the top of the inclined plane is converted to the kinetic energy at the foot of the inclined plane

        The kinetic energy can be mathematically represented as

                    KE = \frac{mv^2}{2} + \frac{Iw}{2}

Where I is the moment of inertia possessed by the hoop  which is mathematically represented as

                 I = mr^2

Here R is the radius of the hoop

         w is the angular velocity which the hoop has at the bottom of the lower part of the inclined plane which is mathematically represented as

                          w = \frac{v}{r}

Where v linear speed of the hoop's center of mass just as the hoop leaves the incline and rolls onto a horizontal surface

      Now expressing the above statement mathematically

            potential \ energy = \frac{mv^2}{y} + \frac{Iw^2}{2}

               mgh = \frac{mv^2}{y} + \frac{Iw^2}{2}

=>            mgh =\frac{mv^2}{2} + \frac{(mr^2)(\frac{v}{r})^2 }{2}  

=>          mgh = \frac{mv^2}{2} + \frac{mv^2}{2}

=>           mgh = mv^2

=>              v = \sqrt{gh}

Substituting values

                v = \sqrt{9.81 * 1.7}

                  v=4.08m/s

4 0
3 years ago
Read 2 more answers
The instantaneous speed of a particle moving along one straight line is v(t) = ate−6t, where the speed v is measured in meters p
beks73 [17]

Answer:

v_max = (1/6)e^-1 a

Explanation:

You have the following equation for the instantaneous speed of a particle:

v(t)=ate^{-6t}   (1)

To find the expression for the maximum speed in terms of the acceleration "a", you first derivative v(t) respect to time t:

\frac{dv(t)}{dt}=\frac{d}{dt}[ate^{-6t}]=a[(1)e^{-6t}+t(e^{-6t}(-6))]  (2)

where you have use the derivative of a product.

Next, you equal the expression (2) to zero in order to calculate t:

a[(1)e^{-6t}-6te^{-6t}]=0\\\\1-6t=0\\\\t=\frac{1}{6}

For t = 1/6 you obtain the maximum speed.

Then, you replace that value of t in the expression (1):

v_{max}=a(\frac{1}{6})e^{-6(\frac{1}{6})}=\frac{e^{-1}}{6}a

hence, the maximum speed is v_max = ((1/6)e^-1)a

5 0
2 years ago
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