Answer:
Explanation:
Attach is the net ionic equation
Label the signals due to ha, hb, and hc in the 1h nmr spectra.
1 answer:
Structure along with ¹H-NMR is shown below.
Signal for Hₐ;
Based on multiplicity of of the peak, a Singlet peak (the only singlet peak present in spectrum) at 2.2 ppm was assigned to Hₐ. As the methyl group in not coupling with any other proton so it gave a singlet peak.
Signal for Hb;
Based on multiplicity of of the peak, a Quartet peak (the only quartet peak present in spectrum) at 2.4 ppm was assigned to Hb. As the methylene group in coupling with methyl group having three protons so it gave a Quartet peak.
Signal for Hc;
Based on multiplicity of of the peak, a Triplet peak (the only triplet peak present in spectrum) at 1.1 ppm was assigned to Hc. As the methyle group in coupling with methylene group having two protons so it gave a Triplet peak.
Signal for Hₐ;
Based on multiplicity of of the peak, a Singlet peak (the only singlet peak present in spectrum) at 2.2 ppm was assigned to Hₐ. As the methyl group in not coupling with any other proton so it gave a singlet peak.
Signal for Hb;
Based on multiplicity of of the peak, a Quartet peak (the only quartet peak present in spectrum) at 2.4 ppm was assigned to Hb. As the methylene group in coupling with methyl group having three protons so it gave a Quartet peak.
Signal for Hc;
Based on multiplicity of of the peak, a Triplet peak (the only triplet peak present in spectrum) at 1.1 ppm was assigned to Hc. As the methyle group in coupling with methylene group having two protons so it gave a Triplet peak.
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Answer:
1) The Kelvin temperature cannot be negative
2) The Kelvin degree is written as K, not ºK
Explanation:
The temperature of an object can be written using different temperature scales.
The two most important scales are:
- Celsius scale: the Celsius degree is indicated with ºC. It is based on the freezing point of water (placed at 0ºC) and the boiling point of water (100ºC).
- Kelvin scale: the Kelvin is indicated with K. it is based on the concept of "absolute zero" temperature, which is the temperature at which matter stops moving, and it is placed at zero Kelvin (0 K), so this scale cannot have negative temperatures, since 0 K is the lowest possible temperature.
The expression to convert from Celsius degrees to Kelvin is:
Therefore in this problem, since the student reported a temperature of -3.5 ºK, the errors done are:
1) The Kelvin temperature cannot be negative
2) The Kelvin degree is written as K, not ºK