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3 years ago

Label the signals due to ha, hb, and hc in the 1h nmr spectra.

Chemistry

1 answer:

trapecia [35]3 years ago

3 0

Structure along with ¹H-NMR is shown below.

Signal for Hₐ;
Based on multiplicity of of the peak, a Singlet peak (the only singlet peak present in spectrum) at 2.2 ppm was assigned to Hₐ. As the methyl group in not coupling with any other proton so it gave a singlet peak.

Signal for Hb;
Based on multiplicity of of the peak, a Quartet peak (the only quartet peak present in spectrum) at 2.4 ppm was assigned to Hb. As the methylene group in coupling with methyl group having three protons so it gave a Quartet peak.

Signal for Hc;
Based on multiplicity of of the peak, a Triplet peak (the only triplet peak present in spectrum) at 1.1 ppm was assigned to Hc. As the methyle group in coupling with methylene group having two protons so it gave a Triplet peak.

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The low-resolution mass spectrum of an unknown analgesic X had a molecular ion of 151. Possible molecular formulas include C7H5N

garik1379 [7]

Answer:

The molecular formula of X is C8H9NO2

Explanation:

Step 1: Data given

exact mass of 151.0640

Molar mass of C = 12 g/mol

Molar mass of H = 1.00783 g/mol

Molar mass of O = 15.9949 g/mol

Molar mass of N = 14.0031 g/mol

Step 2: Calculate molar mass of C7H5NO3

7*12 + 5*1.00783 + 14.0031 + 3*15.9949 = 151.02695 g/mol

Step 3: Calculate molar mass of C8H9NO2

8*12 + 9*1.00783 + 14.0031 + 2*15.9949 = 151.06337 g/mol

Step 4: Calculate molar mass of C10H17N

10*12 + 17*1.00783 + 14.0031 = 151.13621 g/mol

The molecular formula of X is C8H9NO2

3 0

2 years ago

32.33 mL of 1.031 M potassium hydroxide were required to reach the endpoint of a titration of 50.00 mL of nitric acid. What was

tester [92]

The molar concentration of the nitric acid solution was 0.6666 mol/L.

Balanced equation: KOH + HNO_3 → KNO_3 + H_2O

Moles of KOH: 32.33 mL KOH × (1.031 mmol KOH /1 mL KOH)

= 33.33 mmol KOH

Moles of HNO_3: 33.33 mmol KOH× (1 mmol HNO_3/1 mmol KOH)

= 33.33 mmol HNO_3

Concentration of KOH: c = "moles"/"litres" = 33.33 mmol/50.00 mL

= 0.6666 mol/L

4 0

3 years ago

How is carbon- 14 different from carbon-12

Agata [3.3K]

Carbon 12 and carbon 14 are two isotopes of the elements carbon.the difference between carbon 12 and carbon 14 is the number r of neutrons in each atom.the number given after the atom name (carbon) indicates the numbers of protons plus neutron is an atom or iron. Atom of both isotopes of carbon contain 6 protons

8 0

3 years ago

Determine the concentration of a solution (M) made by dissolving 18.8 g of sodium chloride (NaCl) in 750.0 mL of solution.

Viefleur [7K]

Answer:

0.429 M

Explanation:

To find the molarity, you need to (1) convert grams to moles (using the molar mass), then (2) convert mL to L, and then (3) calculate the molarity (using the molarity ratio).

(Step 1)

Molar Mass (NaCl): 22.990 g/mol + 35.453 g/mol

Molar Mass (NaCl): 58.443 g/mol

18.8 grams NaCl 1 mole
-------------------------- x ------------------------ = 0.322 moles NaCl
58.443 grams

(Step 2)

1,000 mL = L

750.0 mL 1 L
------------------ x ----------------- = 0.7500 L
1,000 mL

(Step 3)

Molarity (M) = moles / volume (L)

Molarity = 0.332 moles / 0.7500 L

Molarity = 0.429 M

5 0

1 year ago

If 4.0 mol of NO and 4.0 mol of O2 are combined, how many moles

Masja [62]

4.0

i think it has something to do with molar ratios and finding the limiting reactant

4.0 mol NO * 2 mol NO2/2 mol NO = 4.0 moles of NO2

4.0 mol O2 * 2 mol NO2/1 mol O2 = 8.0 moles of NO2

so the limiting reactant (the reactant that runs out the quickest leaving an excess) is NO

once the limiting reactant is found, we can use that data for that substance to calculate the amount of product

4.0 mol NO * 2 mol NO2/2 mole NO = 4.0 moles of NO2

4 0

3 years ago