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3 years ago

Label the signals due to ha, hb, and hc in the 1h nmr spectra.

Chemistry

1 answer:

trapecia [35]3 years ago

3 0

Structure along with ¹H-NMR is shown below.

Signal for Hₐ;
Based on multiplicity of of the peak, a Singlet peak (the only singlet peak present in spectrum) at 2.2 ppm was assigned to Hₐ. As the methyl group in not coupling with any other proton so it gave a singlet peak.

Signal for Hb;
Based on multiplicity of of the peak, a Quartet peak (the only quartet peak present in spectrum) at 2.4 ppm was assigned to Hb. As the methylene group in coupling with methyl group having three protons so it gave a Quartet peak.

Signal for Hc;
Based on multiplicity of of the peak, a Triplet peak (the only triplet peak present in spectrum) at 1.1 ppm was assigned to Hc. As the methyle group in coupling with methylene group having two protons so it gave a Triplet peak.

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Question 2 Calculate the pH of a solution that has an acetic acid concentration of 0.05 M and a sodium acetate concentration of

Eva8 [605]

Answer : The pH of the solution is, 4.9

Explanation : Given,

Dissociation constant for acetic acid = $K_a=1.8\times 10^{-5}$

Concentration of acetic acid = 0.05 M

Concentration of sodium acetate = 0.075 M

First we have to calculate the value of $pK_a$ .

The expression used for the calculation of $pK_a$ is,

$pK_a=-\log (K_a)$

Now put the value of $K_a$ in this expression, we get:

$pK_a=-\log (1.8\times 10^{-5})$

$pK_a=5-\log (1.8)$

$pK_a=4.7$

Now we have to calculate the pH of buffer.

Using Henderson Hesselbach equation :

$pH=pK_a+\log \frac{[Salt]}{[Acid]}$

$pH=pK_a+\log \frac{[CH_3COONa]}{[CH_3COOH]}$

Now put all the given values in this expression, we get:

$pH=4.7+\log (\frac{0.075}{0.05})$

$pH=4.9$

Therefore, the pH of the solution is 4.9.

8 0

2 years ago

Heated bricks or blocks of iron were used long ago to warm beds. A 1.49 -kg block of iron heated to 155 Celsius would release ho

AlekseyPX

Specific heat capacity= Quantity of heat/massxΔT
Shc of iron (constant)= 0.4494J/³C for 1g
1.49kg=1490g
Q=1490x(22-155)x0.4494
Q=<span>89057.598J</span>

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3 years ago

Which one is not a form of energy?

yuradex [85]

Please add you assignment.

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2 years ago

Include a map with points where neon can be found.

nalin [4]

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3 years ago

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Fittoniya [83]

Answer:

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2 years ago