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1 answer:
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The magnitude of a vertical electric field that will balance the weight of a plastic sphere of mass 2. 1 g that has been charged to -3. 0 NC is 6.86 × N/C.
An electric field is the physical field that surrounds electrically charged particles and exerts a force on all other charged particles in the field, either attracting or repelling them. It also refers to the physical field of a system of charged particles.
It is given that,
Mass of sphere, m = 2.1 g =0.0021kg
Charge,q = ₋3nC = ₋ 3 ₓ
To balance the weight of a plastic sphere, we must determine the magnitude of the electric field. So,
a = g
E =
E = 6860000 N/C
E = 6.86 × N/C
Hence, the magnitude of the electric field that balances its weight is 6.86 × N/C .
To know more about electric field refer to: brainly.com/question/8971780
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Answer:
The velocity of the shell when the cannon is unbolted is 500.14 m/s
Explanation:
Given;
mass of cannon, m₁ = 6430 kg
mass of shell, m₂ = 73.8-kg
initial velocity of the shell, u₂ = 503 m/s
Initial kinetic energy of the shell; when the cannon is rigidly bolted to the earth.
K.E = ¹/₂mv²
K.E = ¹/₂ (73.8)(503)²
K.E = 9336032.1 J
When the cannon is unbolted from the earth, we apply the principle of conservation of linear momentum and kinetic energy
change in initial momentum = change in momentum after
0 = m₁u₁ - m₂u₂
m₁v₁ = m₂v₂
where;
v₁ is the final velocity of cannon
v₂ is the final velocity of shell
Apply the principle of conservation kinetic energy
Therefore, the velocity of the shell when the cannon is unbolted is 500.14 m/s