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mart [117]
3 years ago
13

The rate at which work is done or energy is used is referred to as what

Physics
1 answer:
Georgia [21]3 years ago
6 0
<span>The rate at which work is done or energy is used is referred to as power. </span>
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Why do atoms do group 1 element lose electrons to form cations
Mrac [35]

Answer:

when a element of 1 group take part in reaction, its atom looses outer electron and form positively charged ions called Cation.

Explanation:

8 0
3 years ago
Plz help me plzzz. I'm begging you
Gnom [1K]

Answer:

a then c then b

Explanation:

6 0
3 years ago
Two cars are traveling at the same constant speed v. Car A is moving along a straight section of the road, while B is rounding a
Kamila [148]

Answer:

Car A is not accelerating, but car B is accelerating

Explanation:

Car A is not accelerating because , it is moving with uniform speed in a particular direction . Therefore its velocity too is not changing .

But car B is accelerating because , though its speed is uniform but its velocity is changing due to change in direction . On a circular path , direction of speed changes every moment . Therefore it has an acceleration called centripetal acceleration . Hence car B has acceleration.

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3 years ago
A 10-turn coil of wire having a diameter of 1.0 cm and a resistance of 0.50 Ω is in a 1.0 mT magnetic field, with the coil orien
n200080 [17]

Answer:

The voltage across the capacitor is 1.57 V.

Explanation:

Given that,

Number of turns = 10

Diameter = 1.0 cm

Resistance = 0.50 Ω

Capacitor = 1.0μ F

Magnetic field = 1.0 mT

We need to calculate the flux

Using formula of flux

\phi=NBA

Put the value into the formula

\phi=10\times1.0\times10^{-3}\times\pi\times(0.5\times10^{-2})^2

\phi=7.85\times10^{-7}\ Tm^2

We need to calculate the induced emf

Using formula of induced emf

\epsilon=\dfrac{d\phi}{dt}

Put the value into the formula

\epsilon=\dfrac{7.85\times10^{-7}}{dt}

Put the value of emf from ohm's law

\epsilon =IR

IR=\dfrac{7.85\times10^{-7}}{dt}

Idt=\dfrac{7.85\times10^{-7}}{R}

Idt=\dfrac{7.85\times10^{-7}}{0.50}

Idt=0.00000157=1.57\times10^{-6}\ C

We know that,

Idt=dq

dq=1.57\times10^{-6}\ C

We need to calculate the voltage across the capacitor

Using formula of charge

dq=C dV

dV=\dfrac{dq}{C}

Put the value into the formula

dV=\dfrac{1.57\times10^{-6}}{1.0\times10^{-6}}

dV=1.57\ V

Hence, The voltage across the capacitor is 1.57 V.

5 0
3 years ago
An electron initially at rest, leaves a cathode and is uniformly accelerated in a
katrin [286]

Answer:

75 km/s^2

Explanation:

Divide the final velocity by the time needed to reach the final velocity.

(1500 m/s) /.02s = 75,000 m/s^2 = 75 km/s^2

3 0
3 years ago
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