The quadratic formula is ![\frac{-b+-\sqrt[2]{b^2-4ac}}{2a}](https://tex.z-dn.net/?f=%5Cfrac%7B-b%2B-%5Csqrt%5B2%5D%7Bb%5E2-4ac%7D%7D%7B2a%7D)
and in the equation ax^2+bx+c=0
so now all you have to do is substitute the numbers into the quadratic formula
Answer:
0, - 6, - 12
Step-by-step explanation:
To find the first 3 terms, substitute n = 1, 2, 3 into the formula
a₁ = 3(- 2)(1 - 1) = 3 × - 2 × 0 = 0
a₂ = 3(- 2)(2 - 1) = 3 × - 2 × 1 = - 6
a₃ = 3(- 2)(3 - 1) = 3 × - 2 × 2 = - 12
First 3 terms are 0, - 6, - 12
It’s bull Peter C your welcome :)
Answer:
Point A to point F and point I to point H would have the ratio of 2:1.
Answer:
Take the alternating sum of the digits in the number, read from left to right. If that is divisible by 11, so is the original number. So, for instance, 2728 has alternating sum of digits 2 – 7 + 2 – 8 = -11. Since -11 is divisible by 11, so is 2728.
