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Alex73 [517]
2 years ago
15

Bats,birds,and people evolution. Help

Chemistry
1 answer:
Troyanec [42]2 years ago
6 0

Answer:

i dont understand ... whats the question?

Explanation:

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Chemicals A and B react according to the equation A + B → C. How will the concentrations of each component of the reaction chang
Sever21 [200]
Over time, as the reaction approaches dynamic equilibrium, the concentrations of A and B will decrease and the concentration of C will increase. This is because chemical reactions tend to shift towards the side of the product(s).

Hope this helps!
6 0
3 years ago
Read 2 more answers
HURRYYY!!!!<br> Convert 7.13 x 10^28 atoms of calcium (Ca) to moles of calcium.
puteri [66]

Answer:

<h2>118,438.5 moles</h2>

Explanation:

To find the number of moles in a substance given it's number of entities we use the formula

n =  \frac{N}{L}\\

where n is the number of moles

N is the number of entities

L is the Avogadro's constant which is

6.02 × 10²³ entities

From the question we have

n =  \frac{7.13 \times  {10}^{28} }{6.02 \times  {10}^{23} }  \\  = 118438.538...

We have the final answer as

<h3>118,438.5 moles</h3>

Hope this helps you

4 0
3 years ago
Calculate the pH during the titration of 20.00 mL of 0.1000 M dimethylamine, (CH3)2NH(aq), with 0.1000 M HCl(aq) after 21.23 mL
Evgesh-ka [11]

The pH value of the solution is mathematically given as

pH=2.35

<h3>What pH value of the solution?</h3>

Question Parameters:

pH during the titration of 20.00 mL of 0.1000 M dimethylamine,

with 0.1000 M HCl(aq) after 21.23 mL of the acid

Generally, the equation for the  Chemical Reaction  is mathematically given as

(CH3)2NH(aq), +Hcl   ---> <---- (CH3)2NH2Cl(aq)

Therefore

HCl=\frac{0.186mol}{41.86}

HCL=0.00444M

WHere

HClaq--->H+(aq)+Cl-(aq)

Hence

H+=0.00444M

pH= -log{H+}

pH=log(0.00444)

pH=2.35

For more information on Chemical Reaction

brainly.com/question/11231920

8 0
2 years ago
What minimum volume of 0.200 m potassium iodide solution is required to completely precipitate all of the lead in 155.0 ml of a
Blababa [14]
First, we write the balanced equation for this reaction:

2KI + Pb(NO₃)₂ → 2KNO₃ + PbI₂

From this equation, we see that there are 2 moles of potassium iodide required for each mole of lead (II) nitrate. Moreover, we may use the formula:

Moles = volume (in L) * molarity

We find the molar relation ship for KI : Pb(NO₃)₂ to be 2 : 1. So:

M₁V₁ = 2M₂V₂

V₁ = 2M₂V₂/M₁
V₁ = 2 * 0.112 * 0.155 / 0.2
V₁ = 0.1736 L


The volume required is 173.6 mL
5 0
3 years ago
When aqueous solutions of potassium fluoride and hydrochloric acid are mixed, an aqueous solution of potassium chloride and hydr
Semmy [17]

Answer:

K⁺ (aq)  +  F⁻ (aq)  +  H⁺ (aq)  +  Cl⁻ (aq)  → KCl (aq) + H⁺ (aq)  +  F⁻ (aq)

Explanation:

KF (aq) +  HCl (aq) →  KCl (aq)  + HF (aq)

KF (aq) → K⁺ (aq) +  F⁻ (aq)

HCl (aq) →  H⁺ (aq)  +  Cl⁻ (aq)

KCl (aq) → K⁺ (aq) +  Cl⁻ (aq)

HF (aq) →  H⁺ (aq)  +  F⁻ (aq)

7 0
3 years ago
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