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inessss [21]
4 years ago
15

Nitrogen and water react to form nitrogen monoxide and hydrogen, like this: N2(g) + 2H2O(g) → 2NO(g) +2H2(g) Also, a chemist fin

ds that at a certain temperature the equilibrium mixture of nitrogen, water, nitrogen monoxide, and hydrogen has the following composition: compound concentration at equilibrium H20 NO H2 0.25 M 1.3 M 0.33 M 1.2 M Calculate the value of the equilibrium constant Kc for this reaction. Round your answer to 2 significant digits
Chemistry
1 answer:
Thepotemich [5.8K]4 years ago
8 0

Answer:

Kc for this reaction is 0.43

Explanation:

This is the equilibrium:

N₂(g) + 2H₂O(g) → 2NO(g) +2H₂(g)

And we have all the concentration at equilibrium:

N₂: 0.25M

H₂ : 1.3M

NO: 0.33M

H₂: 1.2M

They are ok, because they are in MOLARITY. (mol/L)

Let's make the expression for Kc

Kc = ( [NO]² . [H₂]² ) / ([N₂] . [H₂O]²)

Kc = (0.33² . 1.2²) / (0.25 . 1.2²)

Kc = 0.4356

In two significant digits. 0.43

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Explanation:

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4 years ago
Select the correct answer from each drop-down menu. How are real gases different from ideal gases? Real gases differ from ideal
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Read 2 more answers
1. If 20 moles of HCl was placed in 40 liters of an
anastassius [24]

Answer:

A) 0.50 M

Explanation:

The computation of the number of molarity of the NaOH is given below:

As we know that

Molarity = Moles ÷ liters

where

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hence, the molarity of the NaOH  solution is 0.50 M

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8 0
3 years ago
If you were to conduct an experiment to answer the question, "Does the volume of a caffeinated drink affect your reaction time?”
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A Type of Drink

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3 years ago
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Andrew [12]
The intermolecular interactions found between pentane molecules are London-Dispersion Forces.

Explaination:

Step 1:
           Instantaneous Dipole: As the pentane molecule is non polar in nature and the electron density on each molecule is symmetrical. When this symmetrical molecule approaches second symmetrical molecule there disturbance is caused due to repulsion between electrons. Due to repulsion the electrons changes there position and for a small period of time an instantaneous dipole is produced on pentane molecule.

Step 2:
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In this way the process repeats and interactions are developed between the non polar pentane molecules. 
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