Answer:
Butanoic Acid:
I have attached the structure of Butanoic Acid. Please refer to the attachment.
Explanation:
Solution:
First of all, we need to calculate the double bond equivalent (DBE) for the compound given:
Compound = C4H8O2
DBE = (C +1) - (H + X - N)/2
C = no. of carbons
H = no. of Hydrogen
X = no. of Halogens
N = no. of Nitrogen
DBE = (4+1) - (8/2)
DBE = 5-4
DBE = 1
It indicates the presence of 1 double bond in the possible structure.
Further structure can be identified by looking the peak values of the spectrum. So, we have,
2500 - 3300 = it indicates the presence of -COOH group
1720 = it indicates the (C=0) stretching
1200 = It indicates the (C-O) stretching
SO, the possible structure is
Butanoic Acid:
I have attached the structure of Butanoic Acid. Please refer to the attachment.
Answer: The combined gas law is a combination of Boyle's Law and Charles' Law. The relationship between pressure, volume, and absolute temperature are all present in the combined gas law. It is written mathematically as:
PV/T=k (constant)
The constant, k, will also depend on the number of moles and could therefore vary. As long as the number of moles is constant, k, will be a true constant value.
Most combined gas law are worked with a before condition and an after condition. We typically number these conditions of state as 1 and 2 (sometimes initial and final also). So the working form of the combined gas law is:
P1V1/T1=P2V2/T2
Any units will work here for pressure and volume but the temperature must be absolute (Kelvin).
Explanation:
You need to use the ideal gas law (PV=nRT) and solve for n. ((3.50atm•10.0L)/(0.0821(L•atm/mol•K)•304K) = n = 1.40 moles. 1 mole of Cl2 = 70.9 gm/mole. The mass would be 99.43 gm
Option No. 1 at the cathode in both an electrolytic cell and a voltaic cell
Negative ion arrives at the anode, attracted by electrostatic forces, where they lose electrons. Loss of electrons is defined as oxidation.
The reverse process occur at the negative electrode, where positive ions pick up electrons. They are reduced.
Answer:
The unknown substance is Au ( gold)
Explanation:
SiO2 has a high melting point, is insoluble in water but is a very poor conductor. So the statements do not apply here.
F2 is soluble in water, has a melting point way lower than 1064 °C, and isa gas. F2 doesn't apply here.
Au is insoluble in water, has a high melting point, is a good conductor and is hard. Gold applies are all those statements.
Kbr is good soluble in water, and is a bad conductorbecause it is just a powder, and the molecules have no mobility, and therefore it cannot conduct electricity. The unknown substance is not Kbr.
The unknown substance is Au ( gold)