Question

A ball is projected vertically downward at a speed of 4.00 m/s. How far does the bal travel in 1.80 s? What is the velocity of the ball at that time?

Answer 1

Answer:

1) Distance traveled equals 23.1 meters.

2) Final velocity equals 21.658 m/s.

Explanation:

The problem can be solved using second equation of kinematics as

$s=ut+\frac{1}{2}at^{2}$

where

s is the distance covered

u is the initial speed of the ball

a is the acceleration the ball is under

t is time of travel

Applying the given values in the above equation we get

$s=4.0\times 1.8+\frac{1}{2}\times 9.81\times 1.8^{2}\\\\s=23.1meters$

Part 2)

The velocity after 't' time can be obtained using first equation of kinematics.

$v=u+at$

Applying the given values we get

$v=4+9.81\times 1.80\\\\\therefore v=21.658m/s$