Question

Complete each of the following nuclear reactions by determining the missing particle, then name that particle("alpha particle" or "uranium-233", etc.).^14 6C -----> ^14 7N + ________________ + ^0 -1 e ---------> ^40 18Ar

Answer 1

Answer :

Thus, the Beta minus decay of carbon-14 reaction is:

$_{6}^{14}\textrm{C}\rightarrow _{7}^{14}\textrm{N}+_{-1}^0e$    Beta particle

The electron capture equation for the given reaction is:

$_{19}^{40}\textrm{K}+_{-1}^0\textrm{e}\rightarrow _{18}^{40}\textrm{Ar}$

Explanation :

Beta minus decay : It is a type of decay process, in which a neutrons gets converted to proton, an electron and anti-neutrino. In this the atomic mass number remains same.

The beta minus decay equation is represented as,

$_Z^A\textrm{X}\rightarrow _{Z+1}^A\textrm{Y}+_{-1}^0e$

(A is the atomic mass number and Z is the atomic number)

Thus, the Beta minus decay of carbon-14 reaction is:

$_{6}^{14}\textrm{C}\rightarrow _{7}^{14}\textrm{N}+_{-1}^0e$    Beta particle

Electron capture : In this decay process, a parent nuclei absorbs an electron and gets converted into a neutron. Simply, a proton and an electron combines together to form a neutron. Mass number does not change in this process.

The electron capture equation is represented as,  

$_Z^A\textrm{X}+_{-1}^0\textrm{e}\rightarrow _{Z-1}^A\textrm{Y}$

The electron capture equation for the given reaction is:

$_{19}^{40}\textrm{K}+_{-1}^0\textrm{e}\rightarrow _{18}^{40}\textrm{Ar}$