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3 years ago

What is gay lussas law

Chemistry

1 answer:

galben [10]3 years ago

6 0

Gay lussas law:

Gay-Lussac law states that the pressure for a given gas’ mass changes directly to an absolute gas temperature, provided that the volume held to be constant. The mathematical expressions of Gay-Lussac law also correspond to those of Charles Law:

$\frac{P}{T} \text { or } \frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$

This gas law is important because it shows that an increase in gas temperature increases the pressure proportionally (if the volume does not change). Similarly, as the temperature decreases, the pressure decreases proportionally.

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What atoms are in Au(NO2)2

Fiesta28 [93]

Au, N, O ( give me brainliest please)

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2 years ago

For the following reaction, the equilibrium constant Kc is 2.0 at a certain temperature. The reaction is endothermic. What do yo

jeyben [28]

Answer:

The correct answer is : 'the concatenation of NO will increase'.

Explanation:

Any change in the equilibrium is studied on the basis of Le-Chatelier's principle.

This principle states that if there is any change in the variables of the reaction, the equilibrium will shift in the direction to minimize the effect.

If the temperature is increased, so according to the Le-Chatlier's principle , the equilibrium will shift in the direction where increase in temperature occurs.

$2NOBr(g)\rightleftharpoons 2NO(g) + Br_2(g)$

As, this is an endothermic reaction, increasing temperature will add more heat to the system which move equilibrium in the forward reaction with decrease in temperature. Hence, the equilibrium will shift in the right direction.

So, the concatenation of NO will increase.

7 0

3 years ago

A gas within a piston–cylinder assembly undergoes an isothermal process at 400 K during which the change in entropy is −0.3 kJ/K

Karolina [17]

Answer:

W = -120 KJ

Explanation:

Since the piston–cylinder assembly undergoes an isothermal process, then the temperature is constant.

Thus; T1 = T2 = 400K

change in entropy; ΔS = −0.3 kJ/K

Formula for change in entropy is written as;

ΔS = Q/T

Where Q is amount of heat transferred.

Thus;

Q = ΔS × T

Q = -0.3 × 400

Q = -120 KJ

From the first law of thermodynamics, we can find the workdone from;

Q = ΔU + W

Where;

ΔU is Change in the internal energy

W = Work done

Now, since it's an ideal gas model, the change in internal energy is expressed as;

ΔU = m•C_v•ΔT

Where;

m is mass

C_v is heat capacity at constant volume

ΔT is change in temperature

Now, since it's an isothermal process where temperature is constant, then;

ΔT = T2 - T1 = 0

Thus;

ΔU = m•C_v•ΔT = 0

ΔU = 0

From earlier;

Q = ΔU + W

Thus;

-120 = 0+ W

W = -120 KJ

8 0

3 years ago

When balancing redox reactions under basic conditions in aqueous solution, the first step is to:________.

natta225 [31]

Answer:

When balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.

Explanation:

Oxidation-reduction reactions or redox reactions are those in which an electron transfer occurs between the reagents. An electron transfer implies that there is a change in the number of oxidation between the reagents and the products.

The gain of electrons is called reduction and the loss of electrons oxidation. That is to say, there is oxidation whenever an atom or group of atoms loses electrons (or increases its positive charges) and in the reduction an atom or group of atoms gains electrons, increasing its negative charges or decreasing the positive ones.

The oxidation and reduction half-reactions, in a basic medium, adjust the oxygens and hydrogens as follows:

In the member of the half-reaction that presents excess oxygen, you add as many water molecules as there are too many oxygen. Then, in the opposite member, the necessary hydroxyl ions are added to fully adjust the half-reaction. Normally, twice as many hydroxyl ions, OH-, are required as water molecules have previously been added.

In short, you first adjust the oxygens with OH-, then you adjust the H with H₂O, and finally you adjust the charge with e-

So, when balancing redox reactions under basic conditions in aqueous solution, the first step is to balance oxygen.

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3 years ago

A certain solid substance, that is very hard, has a high melting point and is nonconducting unless melted is most likely to be:A

svetlana [45]

Answer: B) KCl

Explanation:

It is an odourless gas with a melting point of of 770°c and a boiling point of about 1420°c, it exists in a white crystalline solid form. KCl is highly water soluble and also soluble in other variety of polar solvent but insoluble in many organic solvents.

7 0

3 years ago

What is gay lussas law​

What is gay lussas law