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4 years ago

What is gay lussas law

Chemistry

1 answer:

galben [10]4 years ago

6 0

<u>Gay lussas law:</u>

Gay-Lussac law states that the pressure for a given gas’ mass changes directly to an absolute gas temperature, provided that the volume held to be constant. The mathematical expressions of Gay-Lussac law also correspond to those of Charles Law:

$\frac{P}{T} \text { or } \frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}$

This gas law is important because it shows that an increase in gas temperature increases the pressure proportionally (if the volume does not change). Similarly, as the temperature decreases, the pressure decreases proportionally.

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The specific reaction rate of a reaction at 492k is 2.46 second inverse and at 528k 47.5 second inverse.find activation energy a

crimeas [40]

Answer:

Ea = 177x10³ J/mol

ko = $1.52x10^{19}$ J/mol

Explanation:

The specific reaction rate can be calculated by Arrhenius equation:

$k = koxe^{-Ea/RT}$

Where k0 is a constant, Ea is the activation energy, R is the gas constant, and T the temperature in Kelvin.

k depends on the temperature, so, we can divide the k of two different temperatures:

$\frac{k1}{k2} = \frac{koxe^{-Ea/RT1}}{koxe^{-Ea/RT2}}$

$\frac{k1}{k2} = e^{-Ea/RT1 + Ea/RT2}$

Applying natural logathim in both sides of the equations:

ln(k1/k2) = Ea/RT2 - Ea/RT1

ln(k1/k2) = (Ea/R)x(1/T2 - 1/T1)

R = 8.314 J/mol.K

ln(2.46/47.5) = (Ea/8.314)x(1/528 - 1/492)

ln(0.052) = (Ea/8.314)x(-1.38x $10^{-4}$

-1.67x $10^{-5}$ xEa = -2.95

Ea = 177x10³ J/mol

To find ko, we just need to substitute Ea in one of the specific reaction rate equation:

$k1 = koxe^{-Ea/RT1}$

$2.46 = koxe^{-177x10^3/8.314x492}$

$1.61x10^{-19}ko = 2.46$

ko = $1.52x10^{19}$ J/mol

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3 years ago

What is gay lussas law​

What is gay lussas law