1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Anton [14]
3 years ago
13

What is gay lussas law​

Chemistry
1 answer:
galben [10]3 years ago
6 0

<u>Gay lussas law​:</u>

Gay-Lussac law states that the pressure for a given gas’ mass changes directly to an absolute gas temperature, provided that the volume held to be constant. The mathematical expressions of Gay-Lussac law also correspond to those of Charles Law:

                     \frac{P}{T} \text { or } \frac{P_{1}}{T_{1}}=\frac{P_{2}}{T_{2}}

This gas law is important because it shows that an increase in gas temperature increases the pressure proportionally (if the volume does not change). Similarly, as the temperature decreases, the pressure decreases proportionally.

You might be interested in
What particle limitation to the widespread of this reusable water bottles? Pls help someone
Sauron [17]

Answer: Plastic water bottles

Explanation:

If you use disposable water bottles, here are some important concerns you should know about how they’re made as well as the problems they cause for the planet, your health, and your wallet.

3 0
3 years ago
What is another name for energy lost through heat and sound?
Arturiano [62]

Answer:Figure 1. Energy losses in an incandescent light bulb are very large; most of the input energy is lost in the form of heat energy. This means that when energy is converted to a different form, some of the input energy is turned into a highly disordered form of energy, like heat. ...

Explanation:

3 0
3 years ago
Read 2 more answers
Describe two ways in which a cell grows.
adelina 88 [10]

Answer:

There are two types of cell division: mitosis and meiosis. Most of the time when people refer to “cell division,” they mean mitosis, the process of making new body cells.

3 0
2 years ago
Please help! BRAINLIEST to right answerrrr
zloy xaker [14]

Answer: from the hotter surface to the colder one

Explanation:

8 0
3 years ago
Read 2 more answers
An aqueous solution in a 55 gallon (208 l drum), characterized by minimal buffering capacity, received 4kg of phenol and 1.5 kg
lianna [129]

An aqueous solution in a 55 gallon (208 l drum), characterized by minimal buffering capacity, received 4kg of phenol and 1.5 kg of sodium phenate. What is the ph of the solution. The pka of phenol = 9.98. Mw of phenol and sodium phenate are 94 g/mol and 116 g/mol, respectively.


Volume of solution = 55 gallons = 208.2 L [ 1 gallon = 3.78 L]

moles of phenol = mass / molar mass = 4000 g / 94 = 42.55 moles

moles of sodium phenate = mass / molar mass = 1500 / 116 = 12.93 moles

pKa of phenol = 9.98

We know that the pH of buffer is calculated using Hendersen Hassalbalch's equation

pH = pKa + log [salt] / [acid]

volume is same for both the sodium phenate and phenol has we can directly take the moles of each in the formula

pH = 9.98 + log [12.93 / 42.55] = 9.46



4 0
3 years ago
Other questions:
  • How are landforms and faults related
    11·1 answer
  • Which of the following causes tornadoes
    12·2 answers
  • ASAP Which of these mixtures would best be separated through distillation?
    6·1 answer
  • Dominic made the table below to organize his notes about mixtures. A 1-column table. The first column labeled properties of mixt
    12·2 answers
  • An acid, like HCI, would...
    5·2 answers
  • I NEED HELP ASAP!!<br> I DOMT KNOW HOW TO DO THIS
    13·1 answer
  • Atmosphere pressure is about 100000 Pa. Calculate the force of the Atmosphere on a person whose Surface area is 2.0m
    7·1 answer
  • What properties does Chlorine have on its own?
    12·1 answer
  • D) Evaluate your answer and explain why your answer makes sense​
    14·1 answer
  • Determine the mass of 10g of CaCO3​
    8·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!