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kakasveta [241]
2 years ago
13

Question 22

Physics
1 answer:
N76 [4]2 years ago
5 0

Answer:

tan theta = -18 / 25 = -35.8 deg

This direction is south of east

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A depressive disorder is classified as a(n) ________ disorder.
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A lab cart flies off the end of a track on a lab table with a horizontal velocity of 2.08 m/s. If it lands 0.96 meters from the
lana [24]

Answer:

Option C. 1.2 m

Explanation:

The following data were obtained from the question:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Height (h) of the table =?

Next, we shall determine the time taken for the lab cart to get to the ground. This can be obtained as follow:

horizontal velocity (u) = 2.08 m/s

Horizontal distance (s) = 0.96 m

Time (t) =?

s = ut

0.96 = 2.08 × t

Divide both side by 2.08

t = 0.96 / 2.08

t = 0.5 s

Finally, we shall determine the height of the table as illustrated below:

Time (t) = 0.5 s

Acceleration due to gravity (g) = 9.8 m/s²

Height (h) of the table =?

h = ½gt²

h = ½× 9.8 × 0.5²

h = 4.9 × 0.25

h = 1.2 m

Thus, the height of the table is 1.2 m

3 0
2 years ago
A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 16.0 when the han
slava [35]

There are mistakes in the question as the unit of speed and height is not mention here.The correct question is here

A student standing on the ground throws a ball straight up. The ball leaves the student's hand with a speed of 16.0m/s when the hand is 1.80m above the ground.How long is the ball in the air before it hits the ground? (The student moves her hand out of the way.)

Answer:

t=3.37s

Explanation:

Given Data

As we have taken hand at origin and positive upward

So given data are

y_{i}=0m\\y_{f}=-1.80m\\v_{i}=16.0m/s\\a=g=9.8m/s^{2}

To find

time taken by the ball before it hits the ground

Solution

By using the common kinematic equation

y_{f}=y_{i}+v_{i}t+0.5at^{2}

Put the given values and find for t

So

-1.80=0+16.0t+(0.5*(-9.8)t^{2} )\\-1.80=16.0t-4.9t^{2}\\ 4.9t^{2}-16.0t-1.80=0

Apply quadratic formula to solve for t

t=\frac{-(-16.0)+\sqrt{(-16)^{2}+4(4.9)(-1.80)} }{2(4.9)}\\ t=3.37s

4 0
3 years ago
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