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Pie
2 years ago
14

A 6.00 cm tall light bulb is placed a distance of 54.2 cm from a double convex lens

Physics
1 answer:
BigorU [14]2 years ago
7 0

Answer:

1 / f = 1 / i + 1 / o       thin lens equation

1 / i = 1 / f - 1 / o    =    (o - f) / (o * f)

i = o * f / (o - f)

i = 54.2 * 12.7 / (54.2 - 12.7) = 16.6 cm    image distance

Image is real and inverted and 16.6 / 54.2 * 6 = 1.94 cm tall

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3 years ago
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GrogVix [38]

Answer:

 x =  0.176 m

Explanation:

For this exercise we will take the condition of rotational equilibrium, where the reference system is located on the far left and the wire on the far right. We assume that counterclockwise turns are positive.

Let's use trigonometry to decompose the tension

      sin 60 = T_{y} / T

      T_{y} = T sin 60

       cos 60 = Tₓ / T

      Tₓ = T cos 60

we apply the equation

       ∑ τ = 0

       -W L / 2 - w x + T_{y} L = 0

 

the length of the bar is L = 6m

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let's calculate

let's use the maximum tension that resists the cable T = 900 N

             x = (6 900 sin 60 - 3 200 9.8) / (700 9.8)

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Therefore the block can be up to 0.176m to keep the system in balance.

5 0
3 years ago
A weightlifter liftsa 1,250-N barbell 2 m in 3 s. how much power was used to lift the barbell?
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I have explained in the paper.

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