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expeople1 [14]
3 years ago
10

As you watch the surfers right away towards the shoreline what is the shoreline

Physics
1 answer:
Sophie [7]3 years ago
3 0
The shoreline would be your reference point.

A reference point, in physics, is some point in space used to illustrate the location or position of other things, relative to this reference point. So in this case, the shoreline is considered as the reference point to locate the position of the surfers.

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Describe the relationship between the Law of Conservation of Matter and balancing equations.
Yuliya22 [10]

Answer:

The mass of the products and reactants are the same on both sides of the equation.

The number of atoms of products and reactants are equal and hence it proves the law of conservation of mass.

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3 0
2 years ago
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Can someone please help with this. "A ball is thrown vertically upward with a speed of 26.6 m/s. How high does it rise? The acce
lubasha [3.4K]

v^2=u^2+2as

0=26.6^2-2x9.8xs

-26.6^2/-2x9.8=s

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8 0
3 years ago
Which considerations are used to calculate a windchill factor? Select two options.
vlada-n [284]

Wind speed and air temperature are used to calculate a windchill factor.

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<u></u>

Wind-chill factor is the reduction of body temperature due to the passing flow of lower-temperature air.

The air temperature  value is always higher than the wind chill numbers. the heat index will be used if the apparent temperature is higher than the air temperature.So, Wind speed and air temperature are mainly used to calculate a windchill factor.

There are many ways, the surface loses its heat through conduction, evaporation,radiation, and convection.The rate of convection depends on  the difference in temperature between the surface and the fluid surrounding the surface and the velocity of that fluid with respect to the surface. The air around the warm surface will be heated, an insulating  layer of warm air forms against the surface.The layer becomes a boundary between two. As the wind speed is high the surface cools down rapidly.

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3 years ago
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Which statement best define percent error? check all that apply.
Art [367]

Percent error is the difference between the experimental value and theoretical value and measures the accuracy of the result found. The larger the error, lesser is the accuracy and vice versa.

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It is a mathematical way of showing accuracy

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6 0
1 year ago
A piece of wire 10 m long is cut into two pieces. One piece is bent into a square and the other is bent into an equilateral tria
aleksandrvk [35]

Answer:

a) in order to be maximum the length of the square wire should be 10m and no cut for making the triangle

b) in order to be minimum the length of the square wire should be 3.84 m and the triangle wire should be 6.16 m

Explanation:

for a square with a side length of a and a equilateral triangle of length b

area square = a²

area triangle = base* height/2

for an equilateral triangle height = base * sin 60 = (√2 / 2 )* base

therefore

area triangle = base* height/2 =  base² (√2 /4) =(√2 /4) b²

the total length of the wire is = square length + triangle length = 4*a + 3*b

therefore

A=a²+(√2 /4) b²

4*a + 3*b=L→ b = (L-4*a)/3

A=  a²+(√2 /4) (L-4*a)²/ 9

the maximum and minimum amount can be found taking the derivative of the area respect with a:

dA/da= 2*a + (√2 /36) 2*(L-4*a)*(-4) = 0

a -(√2 /9) (L-4*a) = 0

a - √2 /9 * L + √2 /9*4*a =0

(√2 /9*4+1)*a = √2 /9 * L

a= √2 /9 * L / (√2 /9*4+1) = √2 /9 * L / (√2 /9*4+1) = √2 /9 * 10 m / (√2 /9*4+1)

a= 0.96 m

therefore

b = (L-4*a)/3 = (10 m - 4*0.96m)/3= 2.053 m

A=a²+(√2 /4) b² = (0.96 m)²+ (√2 /4) (2.053m)² = 2.411 m²

in the extreme cases

a= 10 m/4=2.5 m and b=0

thus A= (2.5 m)² = 6.25 m²

b=10 m/3= 3.33 m and a=0

thus A= (√2 /4) (3.33 m)² = 3.92 m²

therefore minimum area A=3.92 m² with Length 1=4*0.96 m=3.84 m , Length 2 =2.053 m*3 = 6.16 m

the maximum area is A=6.25 m² with Length 1=10 m and Length 2=0 m

7 0
3 years ago
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