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3 years ago

9

Which statement about atmospheric pressure near Earth’s surface is true

2 answers:

notka56 [123]3 years ago

6 0

What are the statements?? I need to know the statements so i can help you.
(You can message me the statements or comment them. I will try and help you as soon as possible :)! )

pantera1 [17]3 years ago

4 0

Answer:

who here is doing plato i am for earth space science who can help me with earth space science if u can please contact me on here plz and thank u

Explanation:

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A young woman was found dead on the side of the road. Two witnesses said they saw and red cadillac hit her and drive off earlier

nignag [31]

I think the answer would be A. Density because many headlights could have the same density, but the rest of the analysis techniques would be specific to that crime.

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3 years ago

Kinetic energy is the energy of ______. It increases with mass ______ and _______ .Potential energy is the energy of _______or__

Alona [7]

Answer:

velocity. height. weight. possition. place. energy. force.

Explanation: 50/50 % chance they are wrong and write.

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4 years ago

Scientific _____ must be supported by observations and results many investigations and are not absolute

n200080 [17]

The correct answer you're looking for would be Theories.

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3 years ago

The engine in an imaginary sports car can provide constant power to the wheels over a range of speeds from 0 to 70 miles per hou

puteri [66]

Answer:

$t=5.3687\ s$ is the time taken by the car to accelerate the desired range of the speed from zero at full power.

Explanation:

Given:

Range of speed during which constant power is supplied to the wheels by the car is $0\ mph\ to\ 70\ mph$ .

Initial velocity of the car, $v_i=0\ mph$

final velocity of the car during the test, $v_f=32\ mph=14.3052\ m.s^{-1}$

Time taken to accelerate form zero to 32 mph at full power, $t=1.2\ s$

initial velocity of the car, $u_i=0\ mph$

final desired velocity of the car, $u_f=64\ mph=28.6105\ m.s^{-1}$

Now the acceleration of the car:

$a=\frac{v_f-v_i}{t}$

$a=\frac{14.3052-0}{1.2}$

$a=11.921\ m.s^{-1}$

Now using the equation of motion:

$u_f=u_i+a.t$

$64=0+11.921\times t$

$t=5.3687\ s$ is the time taken by the car to accelerate the desired range of the speed from zero at full power.

8 0

3 years ago

The x component of vector is -27.3 m and the y component is +43.6 m. (a) What is the magnitude of ? (b) What is the angle betwee

lara [203]

Answer:51.44 units

Explanation:

Given

x component of vector is $-27.3\hat{i}$

y component of vector is $43.6\hat{j}$

so position vector is

$r=-27.3\hat{i}+43.6\hat{j}$

Magnitude of vector is

$|r|=\sqrt{27.3^2+43.6^2}$

$|r|=\sqrt{2646.25}$

|r|=51.44 units

Direction

$tan\theta =\frac{43.6}{-27.3}=-1.597$

vector is in 2nd quadrant thus

$180-\theta =57.94$

$\theta =122.06^{\circ}$

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3 years ago