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svp [43]
4 years ago
9

Which statement about atmospheric pressure near Earth’s surface is true

Physics
2 answers:
notka56 [123]4 years ago
6 0
What are the statements?? I need to know the statements so i can help you.
(You can message me the statements or comment them. I will try and help you as soon as possible :)! )

pantera1 [17]4 years ago
4 0

Answer:

who here is doing plato i am for earth space science who can help me with earth space science if u can please contact me on here plz and thank u

Explanation:

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A boy uses a force to keep a rock from falling. (He is carrying the rock.) Some forces, like this one, act only when two objects
MArishka [77]
Gravity is a non contact force , jump from a little high place (don't do that :P) , you wont just get stuck in the air you will fall down , this is gravity you dont need any contact 
5 0
4 years ago
A solid yellow stripe is to be painted in the middle of a certain highway. If 1 gallon of paint covers an area of p square feet
marin [14]

Answer:

option A is correct

Explanation:

Given:

The length to be painted = m miles

The width to be painted = t inches

Area painted in 1 gallon = p square feet

Converting the every given dimension in feet, we have

length to be painted = m × 5280 feet

width to be painted = t/12 feet

area to be painted = (m × 5280 feet) × t/12 feet

now, applying the unitary method, we have

p square feet is painted ⇒ 1 gallon

1 square feet is painted ⇒ 1/p gallon

(m × 5280 feet) × t/12 feet  square feet is painted ⇒ [(m × 5280 feet) × t/12 feet ] × 1/p gallon

thus, we get the gallons of paint required as 5820 mt/12p

hence option A is correct

3 0
4 years ago
Anyone know the answer ?
nata0808 [166]

Answer:

d

Explanation:

4 0
3 years ago
Read 2 more answers
An 800-kHz radio signal is detected at a point 8.5 km distant from a transmitter tower. The electric field amplitude of the sign
Temka [501]

Answer:

Explanation:

Given that,

Frequency of radio signal is

f = 800kHz = 800,000 Hz.

Distance from transmitter

d = 8.5km = 8500m

Electric field amplitude

E = 0.9 V/m

The average energy density can be calculated using

U_E = ½•ϵo•E²

Where ϵo = 8.85 × 10^-12 F/m

Then,

U_E = ½ × 8.85 × 10^-12 × 0.9²

U_E = 3.58 × 10^-12 J/m²

The average electromagnetic energy density is 3.58 × 10^-12 J/m²

6 0
4 years ago
Read 2 more answers
What instrument will be used to measure the volume of a box​
Anettt [7]

Answer:

A ruler.

Explanation:

Just measure height, length and width and multiply each.

6 0
3 years ago
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