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3 years ago

Which statement about atmospheric pressure near Earth’s surface is true

2 answers:

6 0

What are the statements?? I need to know the statements so i can help you.
(You can message me the statements or comment them. I will try and help you as soon as possible :)! )

pantera1 [17]3 years ago

4 0

Answer:

who here is doing plato i am for earth space science who can help me with earth space science if u can please contact me on here plz and thank u

Explanation:

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Bonnie and Clyde are trying to steal the world's largest diamond from a 10 story

german

Answer:

The speed Clyde will be falling at is 33.72.

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3 years ago

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mina [271]

Please mark me brainliest

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3 years ago

Which of these cultures did NOT make major contributions to astronomy?

Svetlanka [38]

I can't particularly place what Icelandic contributed.

But every other culture contributed majorly.

So I would go for option b.

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3 years ago

A jogger runs at a constant rate of 10.0 m every 2.0 seconds. The jogger starts at the origin and runs in the positive direction

Elis [28]

Answer:

(a) 25 m

(b) 75 m

Explanation:

Given that the jogger runs at a constant rate of 10.0 m every 2.0 seconds.

So, the speed of the jogger,

$v=\frac{10}{2}=5m/s\;\cdots(i)$

Let d be the distance covered by him in time, t s.

As distance=(speed) x (time)

So, $d=vt$

From equation (i)

$\Rightarrow d=5t\;\cdots(ii)$

As the jogger starts from origin, so, the distance, $d$ , also represents the position of the jogger at the time $t$ s.

The position-time graph has been shown.

(a) From equation (ii), for t=5.0 s

$d=5\times 5=25 m$

So, the jogger is at a distance of 25 m from the origin.

(b) Similarly, for t=15.0 s

$d=5\times 15=75 m$

So, the jogger is at a distance of 75 m from the origin.

8 0

3 years ago

A body in simple harmonic motion has a displacement x that varies in time t according to the equation x = 5cos(π t + π/3) , wher

zhuklara [117]

Answer:

1/2 Hz

Explanation:

A simple harmonic motion has an equation in the form of

$x(t) = Acos(\omega t - \phi)$

where A is the amplitude, $\omega = 2\pi f$ is the angular frequency and $\phi$ is the initial phase.

Since our body has an equation of x = 5cos(π t + π/3) we can equate $\omega = \pi$ and solve for frequency f

$2\pi f = \pi$

f = 1/2 Hz

7 0

3 years ago

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