<u>Answer</u>:
The coefficient of static friction between the tires and the road is 1.987
<u>Explanation</u>:
<u>Given</u>:
Radius of the track, r = 516 m
Tangential Acceleration 
= 3.89 m/s^2
Speed,v = 32.8 m/s
<u>To Find:</u>
The coefficient of static friction between the tires and the road = ?
<u>Solution</u>:
The radial Acceleration is given by,
Now the total acceleration is
=>
=>
=>
=>
The frictional force on the car will be f = ma------------(1)
And the force due to gravity is W = mg--------------------(2)
Now the coefficient of static friction is
From (1) and (2)
Substituting the values, we get
Answer:
c. 48 cm/s/s
Explanation:
Anna Litical and Noah Formula are experimenting with the effect of mass and net force upon the acceleration of a lab cart. They determine that a net force of F causes a cart with a mass of M to accelerate at 48 cm/s/s. What is the acceleration value of a cart with a mass of 2M when acted upon by a net force of 2F?
from newtons second law of motion ,
which states that change in momentum is directly proportional to the force applied.
we can say that
f=m(v-u)/t
a=acceleration
t=time
v=final velocity
u=initial velocity
since a=(v-u)/t
f=m*a
force applied is F
m =mass of the object involved
a is the acceleration of the object involved
f=m*48.........................1
in the second case ;a mass of 2M when acted upon by a net force of 2F
f=ma
a=2F/2M
substituting equation 1
a=2(M*48)/2M
a=. 48 cm/s/s
A baseball would hit the bat harder. This is because the baseball is a lot heavier and more dense than the plastic ball. The keyword that you're looking for is density. The baseball is dense.
