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IgorC [24]
3 years ago
10

Apply the impulse-momentum relation and the work-energy theorem to calculate the maximum value of t if the cake is not to end up

on the floor. assume that the cake moves a distance d while still on the tablecloth and therefore a distance r?d while sliding on the table top. assume that the friction forces are independent of the relative speed of the sliding surfaces. you can easily try this trick yourself by pulling a sheet of paper out from under a glass of water, but have a mop handy just in case!
Physics
1 answer:
loris [4]3 years ago
8 0
Puto chupame el semen ok? right?
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A ball is thrown upward at time t=0 from the ground with an initial velocity of 8 m/s (~ 18 mph). What is the total time it is i
evablogger [386]

Answer:

The total time it is in the air for the ball is 1.6326 s

Given:

Initial velocity = 8 \frac{m}{s}

To find:

the total time it is in the air = ?

Formula used:

t = \frac{v-u}{a}

Where t = time to reach maximum height

v = final velocity of the ball = 0 m/s

u = initial velocity of ball = 8 m/s

a = acceleration due to gravity = -9.8

Acceleration of gravity is taken as negative because ball is moving in opposite direction.

Solution:

A ball is thrown upward at time t=0 from the ground with an initial velocity of 8 m/s.

The time taken by the ball to reach the maximum height is given by,

t = \frac{v-u}{a}

Where t = time to reach maximum height

v = final velocity of the ball = 0 m/s

u = initial velocity of ball = 8 m/s

a = acceleration due to gravity = -9.8

Acceleration of gravity is taken as negative because ball is moving in opposite direction.

t = \frac{0-8}{-9.8}

t = 0.8163 s

Thus, time taken by the ball to reach the ground again = time taken to reach maximum height

So, Total time required for ball to reach ground = 2t = 2 × 0.8163

Total time required for ball to reach ground = 1.6326 s

The total time it is in the air for the ball is 1.6326 s

4 0
3 years ago
Determine the displacement of a plane that is uniformly accelerated from 66 m/s to 88 m/s in 12 sec
Llana [10]
Determined the displacement of a plane is 66 m:s
5 0
3 years ago
g You want to make simultaneous measurements of the position and momentum of an electron and a proton that are moving along a st
Maslowich

Answer:

1832

Explanation:

From;

Δp Δx = h/4π

Δp = uncertainty in momentum

Δx = uncertainty in position

h= Plank's constant

But p =mv hence, Δp= Δmv

m= mass, v= velocity

mass of electron = 9.11 * 10^-31 Kg

Mass of proton = 1.67 * 10^-27 Kg

since m is a constant,

Δv = h/Δxm4π

For proton;

Δv = 6.6 * 10^-34/4 * 3.14 * 1.67 * 10^-27 * 1 * 10^-10

Δv = 315 ms-1

For electron;

Δv = 6.6 * 10^-34/4 * 3.14 * 9.11 * 10^-31 * 1 * 10^-10

Δv = 577000 ms-1

Ratio of uncertainty of electron to that of proton = 577000 ms-1/315 ms-1= 1832

7 0
2 years ago
1. A bag dropped from a helicopter falls with an acceleration of 9.8m/s2. What is its velocity after 5s?
Tanzania [10]

Answer:

The answer is 49m/s.

Explanation:

Given,

acceleration (a) =9.8m/s^2

initial velocity (u)=0 (as it was in rest condition in helicopter)

time (t) =5 s

now, final velocity (v) after 5s =?

we have,

a =  \frac{v - u}{t}

or \: 9.8 =  \frac{v - 0}{5}

or, v = 49m/s

Therefore, the velocity after 5s is 49m/s.

<em><u>Hope</u></em><em><u> </u></em><em><u>it helps</u></em><em><u>.</u></em><em><u>.</u></em>

5 0
2 years ago
A parallel-plate capacitor in air has circular plates of radius 3.0 cm separated by 1.1 mm. Charge is flowing onto the upper pla
Yuki888 [10]

Answer:

2 x 10^14 N/Cs

Explanation:

radius, r = 3 cm

Area , A = 3.14 x 3 x 3 = 28.26 cm^2 = 28.26 x 10^-4 m^2

d = 1.1 mm = 1.1 x 10^-3 m

i = 5 A

Let time be t and electric field strength is E.

Charge, q = i x t = 5 t

q = C V

q = C x E x d

5 t = \frac{\varepsilon _{0}A}{d}\times E\times d

E/t = \frac{5}{\varepsilon _{0}A}

E/t = \frac{5}{8.854\times 10^{-12}\times 28.26\times 10^{-4}}

E/t = 2 x 10^14 N/Cs

5 0
3 years ago
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