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sveta [45]
3 years ago
10

Consider the reaction below. C2H4(g) + H2(g) to C2H6(g) Which change would likely cause the greatest increase in the rate of the

reaction?
a decrease temperature and decrease pressure
b increase temperature and decrease pressure
c decrease temperature and increase pressure
d increase temperature and increase pressure
Chemistry
2 answers:
mr_godi [17]3 years ago
6 0

Answer: Option (d) is the correct answer.

Explanation:

In the given reaction, C_{2}H_{4}(g) + H_{2}(g) \rightarrow C_{2}H_{6}(g) greatest increase in rate of reaction only occur when we increase the temperature and also increase the pressure.

This is because increase in pressure will bring the molecules closer to each other whereas increase in temperature will help in more number of collisions between reactant molecules.

Thus, this will lead to increase in formation of products. Hence, we can conclude that rate of reaction will increase with increase in temperature and increase in pressure.

algol [13]3 years ago
4 0
D. Increase temperature and increase pressure
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You have to make 500 mL of a 1.50 M BaCl2. You have 2.0 M barium chloride solution available. Determine how to make the needed d
Inga [223]

Answer:

You need 375 mL of BaCl2 solution.

Explanation:

M1V1=M2V2

Dilution formula. Substitute known values and solve for V1.

M1 = 2.0 M

M2 = 1.50 M

V2 = 500 mL

(2.0 M)(V1) = (1.50 M)(500 mL)

V1 = (1.50 M)(500 mL) / (2.0 M)

V1 = 375 mL

7 0
2 years ago
Which subatomic particle accounts for magnetism ?
Natalija [7]

Answer:

Each atom has electrons, particles that carry electric charges. Spinning like tops, the electrons circle the nucleus, or core, of an atom. Their movement generates an electric current and causes each electron to act like a microscopic magnet

Explanation:

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4 0
1 year ago
A sample of 17.0 M concentrated H2SO4 stock solution with a volume of 25.0 cm3 was diluted to final concentration of 5.0 M H2SO4
Art [367]

Answer:

60 cm³ of water

Explanation:

We'll begin by calculating the volume of the diluted solution. This can be obtained as follow:

Concentration of stock solution (C₁) = 17 M

Volume of stock solution (V₁) = 25 cm³

Concentration of diluted solution (C₂) = 5 M

Volume of diluted solution (V₂) =?

C₁V₁ = C₂V₂

17 × 25 = 5 × V₂

425 = 5 × V₂

Divide both side by 5

V₂ = 425 / 5

V₂ = 85 cm³

Thus, the volume of the diluted solution is 85 cm³

Finally, we shall determine the volume of water needed to dilute the solution. This can be obtained as follow:

Volume of stock solution (V₁) = 25 cm³

Volume of diluted solution (V₂) = 85 cm³

Volume of water =?

Volume of water = V₂ – V₁

Volume of water = 85 – 25

Volume of water = 60 cm³

Therefore, 60 cm³ of water is needed to dilute the solution.

6 0
2 years ago
Classify the carbohydrate tagatose by both the carbonyl group and the number of carbon atoms. D-tagatose is sugar with six carbo
Bingel [31]

Answer:

Hexose category and ketohexose category

Explanation:

The classification of the Carbohydrate tagatose by carbonyl group is that it is a monosaccharide and has a hexose structure hence it belongs to the Hexose category

Based on the number of carbon atoms the structure has a ketofunctionality hence it is classified under the ketohexose category

Attached below is the remaining part of the solution

6 0
2 years ago
Suppose 215 g of NO3- flows into a swamp each day. What volume of CO2 would be produced each day at 17.0°C and 1.00 atm?
charle [14.2K]

Answer:

The answer is "41.23 \ L\  N_2"

Explanation:

2 NO_3^{-} + 10 e^{-} + 12 H^{+} \longrightarrow N_2 + 6 H_2O\\\\= \frac{( 215 \ g \ NO_3^{-})}{(62.0049  \frac{\ g NO_3^{-}}{mol})} \times  \frac{(1 \ mol \ N_2}{ 2 \ mol \ NO_3^{-})}\\\\

=3.46746789 \times 0.5\\\\= 1.733 \ mol \ N_2 \\\\\to V = \frac{nRT}{P} \\\\= (1.733 \ mol) \times (0.08205746 \frac{L\ atm}{Kmol}) \times \frac{ (17 + 273) K}{(1.00 atm)}\\\\= 41.23

8 0
3 years ago
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