Answer:
Ionic character
A. PF₃ > PBr₃ > PCl₃
B. BF₃ > CF₄ > NF₃
C. TeF₄ > BrF₃ > SeF₄
Explanation:
The most electronegative element is fluorine, followed chlorine, phosphorous nitrogen etc.
- Atoms with high electronegativity tend to form negative ions.
- Ionic compounds formed between elements with high electronegativity difference.
- % ionic character is directly proportional to electronegativity difference.
- According to Pauling Scale E.n for F(4.0), O(3.5), N(3.0), C(2.5), B(2.0), P(2.19), Se(2.55) , Te (2.1), Cl(3.16) and Br(2.96)
- ΔE.N (Electronegativity difference) between( P and F = 4 - 2.19 = 1.81), (P and Br = 2.96 - 2.19 = 0.77) , (P and Cl = 3.16 - 2.96 = 0.2 )
- ΔE.N (Electronegativity difference) between( N and F = 4 - 3 = 1), (B and F = 4 - 2 = 2) , (C and F = 4 - 2.5 = 1.5 )
- ΔE.N (Electronegativity difference) between( Se and F = 4 - 2.55 = 1.45), (F and Te = 4 - 2.1 = 1.9) , (F and Br = 4 - 2.19 = 1.81 )
Answer:
Br^-1
Explanation:
It is an ion that gained an extra electron making it 36 electrons but the other. one is in the neutral state with 35 electrons
Remember that
- For being a bond covalent ∆E<1.8
- For being a bond ionic ∆E>1.8
#1
Carbon is present so it's covalent
#2
#3
- P-H will hardly form a bond
#4
#5
Answer:
D. Communication of results
