1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
Zina [86]
3 years ago
6

Choose all the answers that apply. Models are used to observe phenomena which _____. happen too slowly} happen too quickly} are

too large} are too small } are too dangerous
Physics
2 answers:
bazaltina [42]3 years ago
8 0

your answer is phenomena which are too large


Paraphin [41]3 years ago
4 0

Answer:


All of these answer are used in models.

Explanation:


The use of models is fundamentals tool in science. Scientists used the models to observe phenomena which happen too slowly, or happen too quickly or may to large or small process and how to extent it may dangerous for firsthand. They used different model depending upon whether which type of question is investigating.



You might be interested in
How does the elbow medical and lateral epicondylitis?
dlinn [17]
<span>Lateral epicondylitis, or “tennis elbow,” is an inflammation of the tendons that join the forearm muscles on the outside of the elbow. </span>The bony bump on the outside (lateral<span> side) of the </span>elbow<span> is called the </span>lateral epicondyle<span>. The ECRB muscle and tendon is usually involved in </span>tennis elbow<span>. </span><span>
Medial epicondylitis, or “golfer’s elbow,” is an inflammation of the tendons that attach your forearm muscles to the inside of the bone at your elbow. </span>It's identified by pain from the elbow to the wrist on the inside (medial<span> side) of the elbow. The pain is caused by damage to the tendons that bend the wrist toward the palm.</span>
4 0
3 years ago
Cobaltâ’60 is a radioactive isotope used to treat cancers of the brain and other tissues. A gamma ray emitted by an atom of this
Crank

Energy of gamma rays is given by equation

E = h\nu

here we know that

h = Planck's constant

\nu = frequency

now energy is given as

E = 4.70 MeV = 4.70 \times 10^6 \times 1.6 \times 10^{-19}

E = 7.52 \times 10^{-13} J

now by above equation

E = h\nu

7.52 \times 10^{-13} = 6.6 \times 10^{-34} \nu

\nu = 1.14 \times 10^{21} Hz

now for wavelength we can say

\lambda = \frac{c}{\nu}

\lambda = \frac{3\times 10^8}{1.14 \times 10^{21}}

\lambda = 2.63 \times 10^{-13} m

3 0
3 years ago
Why are different constellations<br> of stars seen during different<br> seasons?
slamgirl [31]
Actually, they're not.  There's a group of stars and constellations arranged
around the pole of the sky that's visible at any time of any dark, clear night,
all year around.  And any star or constellation in the rest of the sky is visible
for roughly 11 out of every 12 months ... at SOME time of the night. 

Constellations appear to change drastically from one season to the next,
and even from one month to the next, only if you do your stargazing around
the same time every night.

Why does the night sky change at various times of the year ?  Here's how to
think about it:

The Earth spins once a day. You spin along with the Earth, and your clock is
built to follow the sun . "Noon" is the time when the sun is directly over your
head, and "Midnight" is the time when the sun is directly beneath your feet.

Let's say that you go out and look at the stars tonight at midnight, when you're
facing directly away from the sun.

In 6 months from now, when you and the Earth are halfway around on the other
side of the sun, where are those same stars ?  Now they're straight in the
direction of the sun.  So they're directly overhead at Noon, not at Midnight.

THAT's why stars and constellations appear to be in a different part of the sky,
at the same time of night on different dates.
5 0
3 years ago
Read 2 more answers
At the outer edge of a rotating space habitat, 130 m from the center, the rotational acceleration is g. What is the rotational a
enyata [817]

Answer:

Explanation:

Given:

R1 = 130 m

R2 = 65 m

w^2R = g

Assume, g = 9.81 m/s^2

w^2 = 9.81/130

w = 0.275 rad/s

At R2 = 65 m

g = w^2R

= (0.275^2) × 65

= 4.905 m/s^2

In conclusion,

g × R = k

g1/R1 = g2/R2

g2 = (g1 × 65)/130

= g1 ×1/2

= g1/2

6 0
3 years ago
Which are the three types of mutations?
WITCHER [35]
Replication, Multiplication, and Substitution.
7 0
3 years ago
Other questions:
  • Agility refers to a person's level of flexibility.
    5·1 answer
  • Hydrogen/hydronium ion concentration
    12·1 answer
  • An unknown charged particle passes without deflection through crossed electric and magnetic fields of strengths 187,500 V/m and
    9·1 answer
  • Calculate the momentum of a 1,500 kg car traveling at 6 m/s.
    5·1 answer
  • What is the relationship between the strength of an
    15·1 answer
  • Sir William Herschel counted the number of stars in different directions, and getting similar numbers in each direction along th
    12·1 answer
  • Water enters a centrifugal pump axially at atmospheric pressure at a rate of 0.09 m3/s and at a velocity of 3 m/s, and it leaves
    14·1 answer
  • How are rainbows formed? Please explain.
    13·2 answers
  • A boat is rowed perpendicular to the shore of a river that flows at 3.0 m/s as shown in the
    15·1 answer
  • Best answer gets brainliest!
    6·2 answers
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!