A uniform electric field has a magnitude 1.80 kV/m and points in the +x direction. (a) What is the electric potential difference
between x = 0.00 m plane and the x = 3.60 m plane? V(3.60 m) = kV (b) A point particle that has a charge of +2.90 µC is released from rest at the origin. What is the change in the electric potential energy of the particle as it travels from the x = 0.00 m plane to the x = 3.60 m plane?
When you add more water to the balloon, it makes it heavier. Therefore it would weigh the balloon down ( increasing mass) and increasing the energy to plummet down. So the answer is B.
