Answer:
3.117 m
Explanation:
Given that:
the distance of separation between speaker A and speaker B (L) = 6.69 m
Frequency (F) = 750 -Hz tone
Velocity of speed of sound = 343 m/s
The distance from Speaker A to the first point (L₁) on the line can be calculated by using the formula:
where A = 
we have:
∴ the distance from speaker A to the first point on the line between the speakers where constructive interference occurs = 3.117 m
Answer:
Pascal Law's says that:
If the area of one end of a U-tube is A, and the area of the other end is A'. then if we apply a force F in the first end (the one of area A), the force experienced at the other end must be:
F' = F*(A'/A).
b) Now we can apply this to our particular case:
if the area of one end is 0.01m^2, and the area of the other end is 1m^2
Then we have:
A = 0.01m^2
A' = 1m^2
So, if now we apply a force F in the first end, the force experienced at the other end will be:
F' = F*(1m^2/0.01m^2) = F*100
This means that the force in the other end must be 100 times the force in the first end.
Answer:
0.02 sec, 50 Hz
Explanation:
period = 100/5000 = 0.02 sec
frequency = 1/0.02 = 50 Hz
