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2 years ago

A plane took 7 hours to travel 2020 km. For the first 4 hours,

Physics

2 answers:

kicyunya [14]2 years ago

8 0

Answer:

-6.6 km/h

Explanation:

In 7hr plane travelled 2020km;

For the first 4hr the average speed was 310km/h;

d=st, s=d/t;

Distance covered in first 4h is d = 310km/h×4h = 1240km;

See the image attached for further solution

AURORKA [14]2 years ago

3 0

Answer:

260

Explanation:

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Gre4nikov [31]

Explanation:

We use the equation

h = $\frac{gt^2}{2}$ , where

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g is the acceleration due to gravity and

t is the time taken to reach height h.

We can now calculate t to be

$\sqrt{\frac{2*1.2 m}{9.81 m/s^2} }$

= 0.495 s

Let v be the initial velocity of the player.

The player deaccelarates from v m/s to 0 m/s in 0.495 s at the rate of 9.81 m/s^2.

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3 years ago

If you traveled one mile at a speed of 100 miles per hour and another mile at a speed if 1 mile per hour, your average speed wou

Semenov [28]

Answer:

v = 1.98 mph

Explanation:

Given that,

Speed to travel one mile is 100 mph

Speed to travel another mile is 1 mph

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$v=\dfrac{2v_1v_2}{v_1+v_2}$

Putting the values, we get :

$v=\dfrac{2\times 100\times 1}{100+1}$

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3 years ago

How can juggling improve your hand eye coordination?

Ne4ueva [31]

Answer:

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Explanation:

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2 years ago

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Two identical cars A and B are at rest on a loading dock with brakes released. Car C, of a slightly different style but of the s

Nadusha1986 [10]

Answer:

Explanation:

Let the velocity after first collision be v₁ and v₂ of car A and B . car A will bounce back .

velocity of approach = 1.5 - 0 = 1.5

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coefficient of restitution = velocity of separation / velocity of approach

.8 = v₁ + v₂ / 1.5

v₁ + v₂ = 1.2

applying law of conservation of momentum

m x 1.5 + 0 = mv₂ - mv₁

1.5 = v₂ - v₁

adding two equation

2 v ₂= 2.7

v₂ = 1.35 m /s

v₁ = - .15 m / s

During second collision , B will collide with stationary A . Same process will apply in this case also. Let velocity of B and A after collision be v₃ and v₄.

For second collision ,

coefficient of restitution = velocity of separation / velocity of approach

.5 = v₃ + v₄ / 1.35

v₃ + v₄ = .675

applying law of conservation of momentum

m x 1.35 + 0 = mv₄ - mv₃

1.35 = v₄ - v₃

adding two equation

2 v ₄= 2.025

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3 years ago

On Mars, where air resistance is negligible, an astronaut drops a rock from a cliff and notes that the rock falls about d meters

dimulka [17.4K]

Answer:

$d_1 = 16 d$

Explanation:

As we know that initial speed of the fall of the stone is ZERO

$v_i = 0$

also the acceleration due to gravity on Mars is g

so we have

$d = v_i t + \frac{1}{2}gt^2$

now we have

$d = 0 + \frac{1}{2}g t^2$

now if the same is dropped for 4t seconds of time

then again we will use above equation

$d_1 = 0 + \frac{1}{2}g(4t)^2$

$d_1 = 16(\frac{1}{2}gt^2)$

$d_1 = 16 d$

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3 years ago

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