Answer:
37 %.
Explanation:
¡Hola!
En este caso, para el problema descrito, conocemos la corriente de entrada y la de salida del agua, por lo que podemos obtener el flujo de la corriente que contiene el zumo a la salida una vez el agua fue evaporada:
Luego, por medio de un balance de zumo de limón en el evaporador en el cual la cantidad que entra es igual a la que sale con sus respectivas concentraciones:
Como la concentración del zumo a la salida es del 50 % (0.50), la de entrada es:
Que es igual al 37%.
¡Saludos!
Answer:
23.8g
Explanation :
Convert 2.0M into mol using mol= concentration x volume
2.0M x 0.1L (convert 100mL to L since the units for M is mol/L)
= 0.2 mol
We can now find grams by using the molar mass of KBr
=119.023 g/mol (Found online) webqc.org
but can be be calculated by using the molecular weight of K and Br found on the periodic table
We can now calculate the grams by using grams=mol x molar mass
119.023g/mol x 0.2mol
= 23.8046 g
=23.8g (rounded to 1decimal place)
Answer: 1. HYDROCARBONS? 2. ALKANES?
i'm not exactly AMAZING at this but i did some research and this is what i think it is i'm also not in this grade but i tried.
Answer:
Explanation:
Hello!
In this case, since we are considering an gas, which can be considered as idea, we can write the ideal gas equation in order to write it in terms of density rather than moles and volume:
Whereas MM is the molar mass of the gas. Now, since we can identify the initial and final states, we can cancel out R and MM since they remain the same:
It means we can compute the final density as shown below:
Now, we plug in to obtain:
Regards!
