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andrew11 [14]
3 years ago
13

What is the pH value of distilled water?

Chemistry
2 answers:
AVprozaik [17]3 years ago
7 0

Answer:

7

Explanation:

yawa3891 [41]3 years ago
6 0
The ph level should be 7, but because it absorbs carbon dioxide from the atmosphere it’s actually slightly acidic with a pH of 5.8
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An 8 N force is applied to a 2 kg object. What is the magnitude of the object's acceleration? A. 0.25 m/s² B. 4 m/s² C. 6 m/s² D
mel-nik [20]

Answer: 4m/s2 (B)

Explanation:

Force = mass × acceleration

Force given is 8N

Mass=2kg

Acceleration =?

Substitute into the formula

F=ma

8=2a

A=8/2

A=4m/s2

Acceleration used is 4m/s2 (B)

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2 years ago
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What is a polar liquid?
BabaBlast [244]
Polar liquids have both negative and positive ends.
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3 years ago
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How is 1 hectoliter different from 1 kiloliter?
LUCKY_DIMON [66]
1 hectoliter is 26.4172

1 kiloliter is 264.172
5 0
2 years ago
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Calculate the molarity of sodium ion in a solution made
Arada [10]

Answer:

0.1035 M

Explanation:

Considering:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Moles =Molarity \times {Volume\ of\ the\ solution}

Sodium chloride will furnish Sodium ions as:

NaCl\rightarrow Na^{+}+Cl^-

Given :

For Sodium chloride :

Molarity = 0.288 M

Volume = 3.58 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 3.58×10⁻³ L

Thus, moles of Sodium furnished by Sodium chloride is same the moles of Sodium chloride as shown below:

Moles =0.288 \times {3.58\times 10^{-3}}\ moles

Moles of sodium ions by sodium chloride = 0.00103104 moles

Sodium sulfate will furnish Sodium ions as:

Na_2SO_4\rightarrow 2Na^{+}+SO_4^{2-}

Given :

For Sodium sulfate :

Molarity = 0.001 M

Volume = 6.51 mL

The conversion of mL to L is shown below:

1 mL = 10⁻³ L

Thus, volume = 6.51 ×10⁻³ L

Thus, moles of Sodium furnished by Sodium sulfate is twice the moles of Sodium sulfate as shown below:

Moles =2\times 0.001 \times {6.51\times 10^{-3}}\ moles

Moles of sodium ions by Sodium sulfate = 0.00001302 moles

Total moles = 0.00103104 moles + 0.00001302 moles = 0.00104406 moles

Total volume = 3.58 ×10⁻³ L + 6.51 ×10⁻³ L = 10.09 ×10⁻³ L

Concentration of sodium ions is:

Molarity=\frac{Moles\ of\ solute}{Volume\ of\ the\ solution}

Molarity_{Na^+}=\frac{0.00104406}{10.09\times 10^{-3}}

<u> The final concentration of sodium anion = 0.1035 M</u>

4 0
3 years ago
Which kind of material would best accomplish this task ?
timofeeve [1]
What's the question ?
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