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2 years ago

8. If 134 L of Nitrogen gas at STP is combined with 99 L of Chlorine gas at STP,

Chemistry

1 answer:

Blizzard [7]2 years ago

7 0

Answer:

Cl₂ is the limiting reactant.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N₂ + 3Cl₂ —> 2NCl₃

From the balanced equation above,

1 L of N₂ reacted with 3 L of Cl₂.

Finally, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 L of N₂ reacted with 3 L of Cl₂.

Therefore, 134 L of N₂ will react with = 134 × 3 = 402 L of Cl₂.

From the calculation made above, we can see that a higher volume (i.e 402 L) of Cl₂ than what was given (i.e 99 L) is needed to react completely with 134 L of N₂.

Therefore, Cl₂ is the limiting reactant and N₂ is the excess reactant.

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N2(g) + O2(g) → NO(g) ΔHrxn = +90.3 kJ NO(g) + Cl2(g) → NOCl(g) ΔHrxn = –38.6 kJ What is the value of ΔHrxn for the decompositio

Ivanshal [37]

Answer : The value of $\Delta H_{rxn}$ is, -103.4 kJ

Explanation :

According to Hess’s law of constant heat summation, the heat absorbed or evolved in a given chemical equation is the same whether the process occurs in one step or several steps.

According to this law, the chemical equation can be treated as ordinary algebraic expression and can be added or subtracted to yield the required equation. That means the enthalpy change of the overall reaction is the sum of the enthalpy changes of the intermediate reactions.

The given main reaction is,

$2NOCl(g)\rightarrow N_2(g)+O_2(g)+Cl_2(g)$ $\Delta H=?$

The intermediate balanced chemical reaction will be,

(1) $\frac{1}{2}N_2(g)+\frac{1}{2}O_2(g)\rightarrow NO(g)$ $\Delta H_1=+90.3kJ$

(2) $NO(g)+\frac{1}{2}Cl_2(g)\rightarrow NOCl(g)$ $\Delta H_2=-38.6kJ$

Now reversing and multiplying by 2 of reaction 1 and 2 then adding all the equations, we get :

(1) $2NO(g)\rightarrow N_2(g)+O_2(g)$ $\Delta H_1=2\times (-90.3kJ)=-180.6kJ$

(2) $2NOCl(g)\rightarrow 2NO(g)+Cl_2(g)$ $\Delta H_2=2\times (+38.6kJ)=+77.2kJ$

The expression for $\Delta H_{rxn}$ will be,

$\Delta H=\Delta H_1+\Delta H_2$

$\Delta H=(-180.6)+(+77.2)$

$\Delta H=-103.4kJ$

Therefore, the value of $\Delta H_{rxn}$ is, -103.4 kJ

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2 years ago

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List the specific sources of non renewable energy used in 2006

blsea [12.9K]

A list of specific sources of non renewable energy used in 2006 are

- Petroleum[these are natural gases and oils] (28%)

- Natural gases (31.8%)

- coal (17.8%)

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3 years ago

What is the mass of an object that is accelerated 4 m/s2 by a force of 180 N?<br> kg<br> Asap!!!!!!!

muminat

Answer:

<h2>The answer is 45 kg</h2>

Explanation:

The mass of the object can be found by using the formula

$m = \frac{f}{a} \\$

f is the force

a is the acceleration

From the question we have

$m = \frac{180}{4} \\$

We have the final answer as

Hope this helps you

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2 years ago

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A gold block with a mass of 325 g was heated from 22°C to 87°C. How much heat

KonstantinChe [14]

Answer:

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Explanation:

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2 years ago

Which of the following does NOT demonstrate the law of conservation of matter?

Brrunno [24]

The one that does not demonstrates the law of conservation of matter would be the third option: $2NO_2 + H_2O -- > HNO_3 + HNO_2$

<h3>What is law of conservation of matter? </h3>

It is a law that explains that matters are conserved during the course of chemical reactions. They can neither be destroyed nor created.

Thus, the number of moles of the species in a reaction remains the same before and after the reaction.

Thus, an equation that demonstrates the law of conservation of matter will be balanced in terms of the number of moles of species.

The only equation, in this case, is $2NO_2 + H_2O -- > HNO_3 + HNO_2$

There are 3 oxygen species on the reactant while 5 are present on the product side.

More on the law of conservation of matter can be found here: brainly.com/question/9434062

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1 year ago