Question

8. If 134 L of Nitrogen gas at STP is combined with 99 L of Chlorine gas at STP,

Answer 1

Answer:

Cl₂ is the limiting reactant.

Explanation:

We'll begin by writing the balanced equation for the reaction. This is illustrated below:

N₂ + 3Cl₂ —> 2NCl₃

From the balanced equation above,

1 L of N₂ reacted with 3 L of Cl₂.

Finally, we shall determine the limiting reactant. This can be obtained as follow:

From the balanced equation above,

1 L of N₂ reacted with 3 L of Cl₂.

Therefore, 134 L of N₂ will react with = 134 × 3 = 402 L of Cl₂.

From the calculation made above, we can see that a higher volume (i.e 402 L) of Cl₂ than what was given (i.e 99 L) is needed to react completely with 134 L of N₂.

Therefore, Cl₂ is the limiting reactant and N₂ is the excess reactant.