Convert cm into meters,
50/100=0.5m
work done= 10x0.5
=5J
we dont consider the weight of the spring as it acts downwards.
Answer:
At 5km/hr; Hypnotist travels with a higher speed.
Explanation:
Let hypnotist be H while Raul be R.
Given the following data;
Distance H = 5km
Time H = 1 hour
Distance R = 5km
Time R = 2 hours
To find the their respective speed;
a. For H;
Speed = distance/time
Speed H = 5/1
Speed H = 5km/hr
b. For R;
Speed = distance/time
Speed R = 5/2
Speed R = 2.5 km/hr
Therefore, hypnotist travels with a higher speed.
Answer:
The change in momentum is 28265.71 kg-m/s.
Explanation:
Given that,
Mass of a car, m = 877 kg
Initial velocity of the car, u = 0 (at rest)
Final velocity of the car, v = 116 km/h = 32.23 m/s
Time, t = 0.951 s
We need to find the change in momentum produced by the force. It can be calculated as the difference of final momentum and the initial momentum.

So, the change in momentum is 28265.71 kg-m/s.
Answer:
The greatest acceleration the man can give the airplane is 0.0059 m/s².
Explanation:
Given that,
Mass of man = 85 kg
Mass of airplane = 109000 kg
Distance = 9.08
Coefficient of static friction = 0.77
We need to calculate the greatest friction force
Using formula of friction

Where, m = mass of man
g = acceleration due to gravity
Put the value into the formula


We need to calculate the acceleration
Using formula of newton's second law


Put the value into the formula


Hence, The greatest acceleration the man can give the airplane is 0.0059 m/s².
It looks like a refractor.