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igor_vitrenko [27]
3 years ago
5

A 0.0502-kg pair of fuzzy dice is attached to the rearview mirror of a car by a short string. The car accelerates at constant ra

te, and the dice hang at an angle of 3.20° from the vertical because of the car's acceleration. What is the magnitude of the acceleration of the car?
Physics
1 answer:
Sauron [17]3 years ago
7 0

Answer:

a = 0.55 m/s/s

Explanation:

As the car accelerates in forward direction the string will make some angle with the vertical direction

So here horizontal component of the tension force will accelerates the dice in forward direction along with the car

Vertical component of the tension force will balance the weight of the dice

so we will have

Tcos\theta = mg

Tsin\theta = ma

here we know that

\theta = angle made with the vertical by string

now divide the two equations

\frac{sin\theta}{cos\theta} = \frac{ma}{mg}

so we have

a = g tan\theta

a = 9.81 tan3.20

a = 0.55 m/s^2

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A 30kg uniform solid cylinder has a radius of 0.18m. if the cylinder accelerates at 0.023 rad/s^2 as it rotates about an axis th
Nuetrik [128]

Answer:

0.011 N-m

Explanation:

Given that

The mass of a solid cylinder, m = 30 kg

The radius of the cylinder, r = 0.18 m

The acceleration of the cylinder, \alpha =0.023\ rad/s^2

It rotates about an axis through its center. We need to find the torque acting on the cylinder. The formula for the torque is given by :

\tau=I\alpha

Where

I is the moment of inertia of the cylinder,

For cylinder,

I=\dfrac{mr^2}{2}

So,

\tau=\dfrac{mr^2\alpha }{2}\\\\\tau=\dfrac{30\times (0.18)^2\times 0.023 }{2}\\\\\tau=0.011\ N-m

So, the required torque on the cylinder is 0.011 N-m.

7 0
3 years ago
a proton travelling along the x-axis is slowed by a uniform electric field E. at x = 20 cm, the proton has a speed of 3.5x10^6 m
AveGali [126]

Answer:

The magnitude of the electric field is 3.8 × 10⁵⁸ N/C and it is in the negative x- direction.

Explanation:

From work-kinetic energy principles, the kinetic energy change of the proton equals the work done by the electric field.

So, ΔK = W

1/2m(v₂² - v₁²) = qEd where m = mass of proton = 1.673 × 10⁻²⁷ kg, v₁ = initial speed of proton = 3.5 × 10⁶ m/s, v₂ = final speed of proton = 0 m/s, q = proton charge = + e = 1.602 × 10⁻¹⁹ C, E = electric field and d = distance moved by proton = x₂ - x₁ , x₁ = 20 cm and x₂ = 80 cm. So, d = 80 cm - 20 cm = 60 cm = 0.6 m

1/2m(v₂² - v₁²) = qEd

E = (v₂² - v₁²)/2mqd

substituting the values of the variables into E, we have

E = ((0 m/s)² - (3.5 × 10⁶ m/s)²)/(2 × 1.673 × 10⁻²⁷ kg × 1.602 × 10⁻¹⁹ C × 0.6 m)

E = - 12.25 × 10¹² m²/s² ÷ 3.22 × 10⁻⁴⁶

E = -3.8 × 10⁵⁸ N/C

So, the magnitude of the electric field is 3.8 × 10⁵⁸ N/C and it is in the negative x- direction.

6 0
3 years ago
How can I covert these 2,34 meters in decimeters<br>​
zysi [14]

Answer:

If you meant 2.34, 2.34 meters = 23.4 decimeters.

Formula: multiply the value in meters by the conversion factor '10'.

So, 2.34 meters = 2.34 × 10 = 23.4 decimeters.

Hope that helps. x

4 0
2 years ago
Read 2 more answers
Calculate the amount of work done to draw a current of 8A from a point at 100V to a point at 120V in 2 seconds?
Morgarella [4.7K]
Given:
I=8A
t=2second
Potential difference,V=120-100=20volt
Workdone=V×i×t
=20×8×2
=320 joule.
3 0
3 years ago
Why do we add alcohol/ethanol to the leaf once it is boiled?
hichkok12 [17]

Answer:

Complete answer: We boil the leaf in alcohol when we are checking it for starch to eradicate chlorophyll, which is the green pigment present in leaves. ... Hence to dissolve the chlorophyll or the green pigment present in the leaf we boil the leaf in alcohol when we are testing it for starch.

Hope this helps! Have a great day!

4 0
3 years ago
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