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dangina [55]
3 years ago
13

The critical angle for a substance is measured at 53.7 degrees. Light enters from air at 45.0 degrees. At what angle it will con

tinue to travel?
Physics
1 answer:
lys-0071 [83]3 years ago
8 0

Answer:

34.74

Explanation:

Critical angle is represented by the formula

θ(c) = sin^-1 (n2/n1)

And we have been given that the critical angle is 53.7, so we substitute

53.7 = sin^-1 (n2/n1), rearranging, we have

Sin 53.7 = n2/n1

0.8059 = n2/n1

Again, we know that the second medium is air, and the refractive index of air is 1, so

0.8059 = 1/n1, making n1 subject of formula

n1 = 1/0.8059

n1 = 1.24

Now, we have gotten both indices, using Snell's law of refraction, we then find the needed refraction

Sin θ(r) = n(i)/n(r) Sin θ(i)

Now, solving, we have

Sin θ(r) = 1/1.24 * sin 45

Sin θ(r) = 0.8059 * 0.7071

Sin θ(r) = 0.5699

θ(r) = Sin^-1 0.5699

θ(r) = 34.74

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One of your classmates, in a fit of unrestrained ego, jumps onto a lab table:
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The equilibrium condition allows finding the results for the forces of the system are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

Newton's second law indicates that the net force is proportional to the product of the mass and the acceleration of the bodies, in the special case that the acceleration is zero, it is called the equilibrium condition

          ∑ F = 0

Where the bold letters indicate vectors, F is the external forces

a) A free body diagram is a scheme of the forces without the details of the bodies, in the attachmentt we see a free body diagram of the system.

b) The reaction force of the ground is applied in each of the legs of the table, in general this force has the same magnitude in each leg, therefore in Newton's second law we can place it as a single force

             N = N₁ + N₂ + N₃ + N₄₄

Let's apply the equilibrium condition

                N -  W_m -w_{table} = 0

                N =  W_m +w_{table}

                N = M_m g + w_{table}  

They indicate the pose of the boy is 65 kg, for the weight of the table of a laboratory table is approximately 100 N

                N = 65 9.8 + 100

                N = 737 N

c) To calculate the mass of the table we use the relation

                W = m_{table} g

                m_{table} = \frac{w_{table}}{g}

                m_{tabble}= \frac{100}{9.8}  

               m_{table}e = 10.2 kg

In conclusion using the equilibrium condition we can find the results for the forces are

      a) The free body diagram is in the attachment

      b) The normal force is N = 737 N

      c) The mass of the table is  10.2 kg

Learn more here:  brainly.com/question/19860811

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