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Svetllana [295]
3 years ago
10

What is the equation of the horizontal asymptote of the graph of y=1x+5−4?

Mathematics
1 answer:
DanielleElmas [232]3 years ago
6 0
To find the intersection with the axis / zero, replace.
Solve the equation in X

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Is the following relation a function?
grin007 [14]

Answer:

b

Step-by-step explanation:

3 0
3 years ago
Solve 2(1 – x) &gt; 2x<br> this is my question for algebra
Rudik [331]

To solve this, you need to isolate/get the variable "x" by itself in the inequality:

2(1 - x) > 2x     Divide 2 on both sides

\frac{2(1-x)}{2} >\frac{2x}{2}

1 - x > x     Add x on both sides to get "x" on one side of the inequality

1 - x + x > x + x

1 > 2x        Divide 2 on both sides to get "x" by itself

\frac{1}{2} >x  or  x     (x is any number less than 1/2)

[Another way you could've solved it]

2(1 - x) > 2x     Distribute 2 into (1 - x)

(2)1 + (2)(-x) > 2x

2 - 2x > 2x      Add 2x on both sides

2 - 2x + 2x > 2x + 2x

2 > 4x    Divide 4 on both sides to get "x" by itself

\frac{2}{4} >\frac{4x}{4}

\frac{1}{2} >x

6 0
3 years ago
What is the answer to number 5?
Basile [38]
Factor out -x from the expression

3 0
3 years ago
Expand the expression.<br> -70k - 3)
ruslelena [56]

Answer:

-70003

Step-by-step explanation:

-70000 - 3 = - 70003

4 0
3 years ago
The table represents the start of the division of 3x^4+22x^3+37x^2-7x+10<br>by the indicated divisor
andreyandreev [35.5K]
The quotient is x^3 + 4x^2 -x + 1.

Solution:
By polynomial grid division, we start by the divisor 3x + 10 placed on the column headings.
               3x      10
     x^3    3x^4   

We know that 3x^4 must be in the top left which means that the first row entry must be x^3. So the row and column multiply to 3x^4. We use this to fill in all of the first row, multiplying x^3 by the terms of the column entries.
                 3x       10
     x^3      3x^4   10x^3 
     4x^2

We now got 10x^3 though we want 22x^3. The next cubic entry must then be 12x^3 so that the overall sum is 22x^3.
                  3x         10
     x^3      3x^4     10x^3 
     4x^2    12x^3

Now we have 40x^2, so the next quadratic entry must be -3x^2 so that the overall sum is 37x^2.
                 3x          10
     x^3      3x^4      10x^3 
     4x^2    12x^3    40x^2
     -x       -3x^2      -10x

This time we have -10x, so the next linear entry must be 3x so that the overall sum is 7x.
                 3x          10
     x^3      3x^4     10x^3 
     4x^2    12x^3    40x^2
     -x         -3x^2    -10x
     1           3x         10

The bottom and final term is 10, which is our desired answer. Therefore, we can now read the quotient off the first column:
     3x^4+22x^3+37x^2-7x+10 / 3x + 10 = x^3 + 4x^2 -x + 1
8 0
3 years ago
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