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Artist 52 [7]
3 years ago
10

The slotted arm OA rotates about a fixed axis through O. At the instant under consideration, θ = 36°, θ˙ = 36 deg/s, and θ¨ = 26

deg/s2. Determine the magnitude of the force F applied by arm OA and the magnitude of the force N applied by the sides of the slot to the 0.5-kg slider B. Neglect all friction, and let L = 0.72 m. The motion occurs in a vertical plane.
Physics
1 answer:
xz_007 [3.2K]3 years ago
4 0

Answer:

   F = 0.0545 N

Explanation:

Let's use Newton's second law for rotational movement

        τ = I α

The moment of inertia for a bar supported by some ends is

       I = 1/3 m L²

Torque is

            τ = F L

Let's replace

         F L = 1/3 m L² α

         F = 1/3 m L α

Let's reduce angular acceleration to SI units

       Alf = 26º / s² (π rad / 180º) = 0.454 rad / s²

Let's calculate

          F = 1/3  0.5  0.72  0.454

          F = 0.0545 N

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nikdorinn [45]
Velocity is a function of time and defined by both a magnitude and a direction.  Often in physics problems, you will need to calculate the initial velocity (speed and direction) at which an object in question began to travel. There are multiple equations that can be used to determine initial velocity. Using the information given in a problem, you can determine the proper equation to use and easily answer your question. Sorry if this is not what your looking for
6 0
3 years ago
A cylindrical tank of methanol has a mass of 70 kg and a volume of 75 L. Determine the methanol’s weight, density, and specific
dem82 [27]

Answer:

Weight=686.7N, \rho=933kg/m^{3}, S.G.=0.933, F=17.5N

Explanation:

So, the first value the problem is asking us for is the weight of methanol. (This is supposing there is a mass of methanol of 70kg inside the tank). We can find this by using the formula:

W=mg

so we can substitute the data the problem provided us with to get:

W=70kg(9.81m/s^{2})

which yields:

W=686.7N

Next, we need to find the density of methanol, which can be found by using the following formula:

\rho=\frac{m}{V}

we know the volume of methanol is 75L, so we can convert that to m^{3} like this:

75L*\frac{0.001m^{3}}{1L}=0.075m^{3}

so we can now use the density formula to find our the methanol's density, so we get:

\rho=\frac{m}{V}

\rho=\frac{70kg}{0.075m^{3}}

\rho=933.33kg/m^{3}

Next, we can us these values to find the specific gravity of methanol by using the formula:

S.G.=\frac{\rho_{sample}}{\rho_{H_{2}O}}

when substituting the known values we get:

S.G.=\frac{933.33kg/m^{3}}{1000kg/m^{3}}

so:

S.G.=0.933

We can now find the force it takes to accelerate this tank linearly at 0.25m/s^{2}

F=ma

F=(70kg)(0.25m/s^{2})

F=17.5N

6 0
3 years ago
The energy that's given to the body by food is A. measured in units called calories. B. best obtained by eating high protein. C.
mel-nik [20]

Answer:

Calories, however you might want to back up my answer. I havent studied this topic in a while.

4 0
3 years ago
HELP PLS! :/
zlopas [31]

Explanation:

formula: Vi = Vf - (at)

Vi: intial velocity

Vf: final velocity

a: acceleration

t: time

fill in formula with the numbers you are given

Vi= 41.6m - ((9.81 m/s^2)(1.89s))

parenthesis first according to pemdas

Vi= 41.6m - 18.54m/s

Answer: 23.06m/s

disclaimer: I havent done physics in awhile so I have no idea if this is right. just an attempt to help steer you in the right direction hopefully. good luck

7 0
3 years ago
A rescue plane spots a survivor 132 m directly below and releases an emergency kit with a parachute. If the package descends at
borishaifa [10]

Answer: 19.15 meters on the waves away from the survivor.

Explanation:

7 0
3 years ago
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