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Artist 52 [7]
4 years ago
10

The slotted arm OA rotates about a fixed axis through O. At the instant under consideration, θ = 36°, θ˙ = 36 deg/s, and θ¨ = 26

deg/s2. Determine the magnitude of the force F applied by arm OA and the magnitude of the force N applied by the sides of the slot to the 0.5-kg slider B. Neglect all friction, and let L = 0.72 m. The motion occurs in a vertical plane.
Physics
1 answer:
xz_007 [3.2K]4 years ago
4 0

Answer:

   F = 0.0545 N

Explanation:

Let's use Newton's second law for rotational movement

        τ = I α

The moment of inertia for a bar supported by some ends is

       I = 1/3 m L²

Torque is

            τ = F L

Let's replace

         F L = 1/3 m L² α

         F = 1/3 m L α

Let's reduce angular acceleration to SI units

       Alf = 26º / s² (π rad / 180º) = 0.454 rad / s²

Let's calculate

          F = 1/3  0.5  0.72  0.454

          F = 0.0545 N

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Answer:

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Explanation:

Another way to perceive this is 1 G = 9.81 Newtons per Kilogram so 50 G =490.5 Newtons per Kilogram. The 100 gram apple at 1 G has 0.981 Newtons of force and at 50 G has an apparent weight of 5 KG or 49.05N.

7 0
3 years ago
The fusion of deuterium and hydrogen is shown in the equation. fill in the missing number.
stellarik [79]

Answer:

= 2

Explanation:

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During the process of hydrogen fusion a nucleus of deuterium is formed from two protons with emission of a neutrino.

In this case deuterium fuses with hydrogen nuclei to form helium-3 and also release energy.

That is;

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3 years ago
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2. What is the difference between special relativity and general relativity? Briefly describe each theory and cite one piece of
Natali [406]
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7 0
3 years ago
A 25 N force stretches a spring 0.280 m. What was the spring constant?
soldi70 [24.7K]

Answer:

the  spring constant is -89.2857 n/m

Explanation:

The computation of the spring constant is shown below:

As we know that

Force in newtons = Spring constant × amount of extension

F = -k × x

where

F = 25 N

And, x = 0.280m

So, the spring constant would 2  

= 25N ÷ 0.280 m

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3 years ago
Polarized light is incident on three polarizing filters in a row. The initial intensity of the light is 4 W/m^2. The first filte
DiKsa [7]

Answer:

45°

Explanation:

I = Polarized light after 3 filter = 0.5 W/m²

I_0 = Initial light intensity = 4 W/m²

The intensity of polarized light is given by

I=I_0cos^2Acos^245cos^245\\\Rightarrow A=cos^{-1}\sqrt{\dfrac{I}{I_0cos^245cos^245}}\\\Rightarrow A=cos^{-1}\sqrt{\dfrac{0.5}{4\times cos^245\times cos^245}}\\\Rightarrow A=45^{\circ}

Hence, the angle relative to the vertical was the light initially polarized is 45°

4 0
3 years ago
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