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Zielflug [23.3K]
3 years ago
14

Help please I'm need help with number 4, 5 , and 6

Mathematics
2 answers:
Westkost [7]3 years ago
4 0
4= 121 5= 49 6= 169 hope this helps
gavmur [86]3 years ago
4 0
4. to find the area 11x11 is how you get the area 11x11=121
5.7x7=49
6.13x13=169
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Write an equation of a line that passes through the point (4,3) and is perpendicular to the graph of the equation y=−13x+4.
lilavasa [31]

Answer:

y = -13x + 55

Step-by-step explanation:

perpendicular formula : m1 × m2 = -1

y = -13x + 4

now we take the grafient of the equation which is 13 :

m × 13 = -1

m = -13

so now we hv a new gradient then we can find the equation use the formula y = mx + c :

m = -13 point = ( 4 , 3 )

sub them into the formula,

3 = -13 (4) + c

3 = -52 + c

3 + 52 = c

55 = c

c = 55

now we rewrite again the c and the m to become a complete equation : y = -13x + 55

5 0
3 years ago
I need help people help me
sineoko [7]

Answer:

87

Step-by-step explanation:

all the angles of a triangle out of 180 so subtract the two numbers you have from 180

8 0
2 years ago
Read 2 more answers
What is the arrangement of data usually in rows?
zaharov [31]
<span>it depends on what type of format is used.</span>
4 0
3 years ago
S the expression x3•x3•x3 equivalent to x3•3•3
Artyom0805 [142]
Remember
(x^m)(x^n)=x^(m+n)
and difference of 2 perfect squres
(a²-b²)=(a-b)(a+b)
and sum or difference of 2 perfect cubes

so
(x^3)(x^3)(x^3)=x^(3+3+3)=x^9
so

x^9=3*3*x^3
x^9=9x^3
minus 9x^3 both sides
0=x^9-9x^3
factor
0=(x^3)(x^6-9)
factor difference of 2 perfect squraes
0=(x^3)(x^3-3)(x^3+3)
factor differnce or sum of 2 perfect cubes (force 3 into (∛3)³)
0=(x³)(x-∛3)(x²+x∛3+∛9)(x+∛3)(x²-x∛3+∛9)
set each to zero

x³=0
x=0

x-∛3=0
x=∛3

x²+x∛3+∛9=0 has no solution

x+∛3=0
x=-∛3

x²-x∛3+∛9=0 has no solution



so the solutions are
x=-∛3, 0, ∛3
3 0
3 years ago
What's the difference?
Komok [63]
\bf \begin{cases}&#10;(-2x^2)\\&#10;-2x^2&#10;\end{cases}\qquad (-2x^2)-(-2x^2)\implies -2x^2+2x^2\implies ? you tell us
3 0
3 years ago
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