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Ray Of Light [21]
3 years ago
7

a moving ball rolls into a stationary ball. the total momentum of both balls after the collision will be

Physics
2 answers:
rosijanka [135]3 years ago
5 0
The momentum of the rolling ball will have less momentum than before the collision and the stationary ball will have more momentum after the collusion.
Genrish500 [490]3 years ago
3 0

The moving ball exerts a force on the stationary ball.

The stationary ball exerts a force on the moving ball.

When two objects collide, each object exerts a force on the other. Unlike energy, force can’t be transferred between objects. Force has strength and direction, but it isn’t a property of an object.

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a snail can move approximately 0.30 meters per minute.How many meters can the snail cover in 15 minutes ?
hichkok12 [17]
Sometimes if you have the word per, you need to multiply. In this problem, they are asking you to find the amount of meters a snail can travel per minute.They are giving you the amount of minutes, so in this case you multiply 15 times 0.30. The answer is 4.5 meters.

8 0
3 years ago
1)
Ket [755]

Answer:

1) D

2) A

Explanation:

1) Each group has the same number of valence electrons, which are the outer electrons.

2) Ionic bonds are between a metal and non - metal, the metal being sodium and the non - metal being chlorine.

3 0
3 years ago
Which part of the microscope is the circular area on the stage that light passes through?
patriot [66]

Answer: The part of the microscope that is the circular area is the APERTURE

I hope this helped!

6 0
1 year ago
1123123213213242141241
schepotkina [342]

Answer:

thanks for the points

Explanation:

8 0
3 years ago
Three charged particles are positioned in the xy plane: a 50-nC charge at y = 6 m on the y axis, a −80-nC charge at x = −4 m on
disa [49]

Answer:

V = 48 Volts

Explanation:

Since we know that electric potential is a scalar quantity

So here total potential of a point is sum of potential due to each charge

It is given as

V = V_1 + V_2 + V_3

here we have potential due to 50 nC placed at y = 6 m

V_1 = \frac{kQ}{r}

V_1 = \frac{(9\times 10^9)(50 \times 10^{-9})}{\sqrt{6^2 + 8^2}}

V_1 = 45 Volts

Now potential due to -80 nC charge placed at x = -4

V_2 = \frac{kQ}{r}

V_2 = \frac{(9\times 10^9)(-80 \times 10^{-9})}{12}

V_2 = -60 Volts

Now potential due to 70 nC placed at y = -6 m

V_3 = \frac{kQ}{r}

V_3 = \frac{(9\times 10^9)(70 \times 10^{-9})}{\sqrt{6^2 + 8^2}}

V_3 = 63 Volts

Now total potential at this point is given as

V = 45 - 60 + 63 = 48 Volts

3 0
3 years ago
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