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Ray Of Light [21]
3 years ago
7

a moving ball rolls into a stationary ball. the total momentum of both balls after the collision will be

Physics
2 answers:
rosijanka [135]3 years ago
5 0
The momentum of the rolling ball will have less momentum than before the collision and the stationary ball will have more momentum after the collusion.
Genrish500 [490]3 years ago
3 0

The moving ball exerts a force on the stationary ball.

The stationary ball exerts a force on the moving ball.

When two objects collide, each object exerts a force on the other. Unlike energy, force can’t be transferred between objects. Force has strength and direction, but it isn’t a property of an object.

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timama [110]

Answer:

A

Explanation:

The acceleration of an object is directly proportional to its net force.

a =  \frac{f}{m}

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3 years ago
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A 2,000 kg car travels with a tangential
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A= v²/R
a = 12²/30 =4.8 m/s²
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Earth's dynamic processes allow our plant to recycle:
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Earth's dynamic processes allow our planet to recycle air, surface materials, and water. The correct answer is D.
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If a star appears to be very red (like Betelgeuse), it is likely to be in which spectral class?
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It would be spectral class M

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3 years ago
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The velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in
pochemuha

Since g is constant,  the force the escaping gas exerts on the rocket will be 10.4 N

<h3>What is Escape Velocity ?</h3>

This is the minimum velocity required for an object to just escape the gravitational influence of an astronomical body.

Given that the velocity of a 0.25kg model rocket changes from 15m/s [up] to 40m/s [up] in 0.60s. The gravitational field intensity is 9.8N/kg.

To calculate the force the escaping gas exerts of the rocket, let first highlight all the given parameters

  • Mass (m) of the rocket 0.25 Kg
  • Initial velocity u = 15 m/s
  • Final Velocity v = 40 m/s
  • Time t = 0.6s
  • Gravitational field intensity g = 9.8N/kg

The force the gas exerts of the rocket = The force on the rocket

The rate change in momentum of the rocket = force applied

F = ma

F = m(v - u)/t

F = 0.25 x (40 - 15)/0.6

F = 0.25 x 41.667

F = 10.42 N

Since g is constant,  the force the escaping gas exerts on the rocket is therefore 10.4 N approximately.

Learn more about Escape Velocity here: brainly.com/question/13726115

#SPJ1

7 0
2 years ago
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