Ask question

Ask question

All categories

2 years ago

9

If you hold your hand over a pot of boiling water, it feels hot. Explain how the boiling water is transferring heat to your hand

.

2 answers:

disa [49]2 years ago

5 0

by conduction, which is direct touch

Natali5045456 [20]2 years ago

3 0

Explanation:

When we heat a fluid (liquid or gas) then hot material (less dense) will rise to the top and cool material (more dense) will sink at the bottom. Hence, this process of inter mixing of fluids is known as convection.

So, when we hold our hand over a pot of boiling water then due to the convection process taking place we feel heat on our hand. Whereas when there occurs direct touch between two objects of different temperature then this heat transfer is known as conduction.

Thus, we can conclude that the boiling water is transferring heat to your hand through convection.

You might be interested in

Protons and neutrons in an atom are held together by _____.

marysya [2.9K]

Protons and neutrons in an atom are held together by a nuclear energy also called the strong force.

7 0

2 years ago

Two neutron stars are separated by a distance of 1.0 x 1012 m. They each have a mass of 1.0 x 1028 kg and a radius of 1.0 x 103

son4ous [18]

To develop this problem it is necessary to apply the concepts related to Gravitational Potential Energy.

Gravitational potential energy can be defined as

$PE = -\frac{GMm}{R}$

As M=m, then

$PE = -\frac{Gm^2}{R}$

Where,

m = Mass

G =Gravitational Universal Constant

R = Distance /Radius

PART A) As half its initial value is u'=2u, then

$U = -\frac{2Gm^2}{R}$

$dU = -\frac{2Gm^2}{R}$

$dKE = -dU$

Therefore replacing we have that,

$\frac{1}{2}mv^2 =\frac{Gm^2}{2R}$

Re-arrange to find v,

$v= \sqrt{\frac{Gm}{R}}$

$v = \sqrt{\frac{6.67*10^{-11}*1*10^{28}}{1*10^{12}}}$

$v = 816.7m/s$

Therefore the velocity when the separation has decreased to one-half its initial value is 816m/s

PART B) With a final separation distance of 2r, we have that

$2r = 2*10^3m$

Therefore

$dU = Gm^2(\frac{1}{R}-\frac{1}{2r})$

$v = \sqrt{Gm(\frac{1}{2r}-\frac{1}{R})}$

$v = \sqrt{6.67*10^{-11}*10^{28}(\frac{1}{2*10^3}-\frac{1}{10^{12}})}$

$v = 1.83*10^7m/s$

Therefore the velocity when they are about to collide is $1.83*10^7m/s$

7 0

2 years ago

During science class, Ava and Justin were discussing the rotation of the Sun and debating over which model would best illustrate

agasfer [191]

Answer:

it would b B

Explanation:

3 0

2 years ago

A fly travels along the x-axis. His starting point is x = 16 m and his ending point 15x = - 25 m. His flight lasts 4.0 seconds H

gogolik [260]

Explanation:

Starting position at x = 16m

Ending position at x = -25m

Time of flight = 4s

Unknown:

Distance flown = ?

Displacement = ?

Speed = ?

Velocity = ?

Solution:

To find the distance flown, we should understand that the body is moving on the x - plane;

So distance = 16 + 25 = 41m

Displacement is 41m to the left or -x axis

Speed is the distance divided by the time taken;

Speed = $\frac{distance}{time}$ = $\frac{41}{4}$ = 10.25m/s

Velocity is 10.25m/s along -x axis

5 0

2 years ago

A powerful motorcycle can produce an acceleration of 3.00 m/s2 while traveling at 90.0 km/h. At that speed the forces resisting

nata0808 [166]

Answer:

1185 N

Explanation:

From Newton’s second law of motion,

F=ma where m= mass of motorcycle, a is acceleration of the motorcycle and F=Force

Net force acting on motorcycle $F_{net}$ is given by $F_{net}=F-f$

Where F is force acting on motorcycle and f is frictional force

Substituting F-f for $F_{net}$

$F_{net}=ma$ hence ma= F- f Substituting a with 3, m with 245Kg and f with 450N as provided

245*3= F- 450

F=245*3 +450= 1185 N

6 0

2 years ago