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4 years ago

An important part of developing motivation includes understanding that motivation is influenced by your _____.

2 answers:

8 0

An important part of developing motivation includes understanding that motivation is influenced by your actions. Motivation is the desire to achieve a goal or a certain performance level leading to a goal - directed behavior. When a person is motivated it mean that he or she has the desire to accomplish something. It is important specially in the work environment where your performance is being measured. The performance of a person is determined by the persons' ability, his work environment and his motivation. Motivation comes in many forms, salary, benefits, environment and it is up to him or her what he or she chooses.

oee [108]4 years ago

8 0

the answer is positive mindset : )

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Calculate the resultant force acting in the opposite directions:- answer asap

kap26 [50]

Answer:

Magnitude of the resultant force will be 20N in the direction of $F_2$ .

Explanation:

It's given in the question that two forces have been applied on the object given.

Since force is a vector quantity, therefore, it has magnitude and direction both.

$F_1=20N$

$F_2=40N$

Both the forces are in the opposite directions.

Therefore, magnitude of the resultant force of these forces will be,

$F_2-F_1=40-20$

= 20 N

And the direction of the resultant force will be towards $F_2$ .

Therefore, magnitude of the resultant force will be 20N in the direction of $F_2$ .

3 0

3 years ago

HURRY URGENT ASAP I WILL GIVE BRAINLIEST

Leto [7]

Answer:

Explanation:

4 0

3 years ago

Velocity differs from speed in that velocity indicates a particle's __________ of motion.

masha68 [24]

Velocity differs from speed in that velocity indicates a particle's direction of motion.

Therefore, your correct answer is: Direction

Good luck with your studies, I hope this helps~!

5 0

3 years ago

A yo-yo is made from two uniform disks, each with mass m and radius R, connected by a light axle of radius b. A light, thin stri

schepotkina [342]

Answer:

linear acceleration

$a = \frac{2g}{2 + \frac{R}{b}}$

angular acceleration

$\alpha = \frac{2g}{R(2 + \frac{R}{b})}$

Explanation:

As we know that the force due to tension force is upwards while weight of the disc is downwards

so we will have

$2mg - T = 2ma$

also we have

$Tb = (\frac{1}{2}mR^2 + \frac{1}{2}mR^2)\alpha$

now we have

$Tb = mR^2(\frac{a}{R})$

$T = \frac{mRa}{b}$

now we have

$2mg = (2ma + \frac{mRa}{b})$

$a(2 + \frac{R}{b}) = 2g$

so we have

linear acceleration

$a = \frac{2g}{2 + \frac{R}{b}}$

angular acceleration

$\alpha = \frac{2g}{R(2 + \frac{R}{b})}$

4 0

3 years ago

Calculate the angular velocity and linear velocity of both wheels assuming the larger wheel rotates at 120 revolutions per mi

IRINA_888 [86]

120 revolutions per min is (20RPM)
120revolutions is 240 Pi radians (because 1 revolution is 2Pi rad)

angular velocity
w= 240Pixf, f is the frequency and f= 1/T, T =1mn=60s=period, so f=1/60=0.01Hz
so w = 240*Pi*0.01=12.56 rad /s
linear velocity can be found with
V =Rx w,
V=12.56 R the value depends on what value is the radius of both wheels

6 0

3 years ago