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Nadusha1986 [10]
3 years ago
7

Which of the following is a sign of a physical Change ?

Physics
2 answers:
guapka [62]3 years ago
7 0

C.) i believe because the change in shape is changing the physical appearance

galina1969 [7]3 years ago
5 0

<u>Answer:</u>

The correct answer option is C) A change in the shape of a substance.

<u>Explanation:</u>

Physical changes can be defined as the changes which affect the form of a chemical substance but not its chemical composition. These are the changes in which no bonds are broken or formed.

A change in the shape of a substance is a physical change because there is no change in composition of the substance chemically.

While all other options involve a change in chemical composition so they are not the examples of a physical change.

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From the calculations, the value of the acceleration due to gravity is 0.38 m/s^2.

<h3>What is weight?</h3>

The weight of an object is obtained as the product of the mass of the body and the acceleration due to gravity.

Thus;

When;

mass = 120 kg

weight =  46 N

acceleration due to gravity = 46 N/120 kg

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A wave has a frequency of 1000 Hz. If the wavelength is 0.5 m, how fast is the wave<br> traveling?
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2 years ago
A block is pulled across a flat surface at a constant speed using a force of 50 newtons at an angle of 60 degrees above the hori
vladimir2022 [97]

The magnitude of the friction force is 25 N

Explanation:

To solve this problem, we just have to analyze the forces acting on the block along the horizontal direction. We have:

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  • The force of friction, F_f, acting in the backward direction

According to Newton's second law, the net force acting on the block in the horizontal direction must be equal to the product between the mass of the block and its acceleration:

\sum F_x = ma_x

where

m is the mass of the block

a_x is the horizontal acceleration

However, the block is moving at constant speed, so the acceleration is zero:

a_x = 0

So the equation becomes

\sum F_x = 0 (1)

The net force here is given by

\sum F_x = F cos \theta - F_f (2)

And so, by combining (1) and (2), we find the magnitude of the friction force:

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3 years ago
If the rectangular barge is 3.0 m by 20.0 m and sits 0.70 m deep in the harbor, how deep will it sit in the river?
leva [86]

The harbour contains salt water while the river contains fresh water. So assuming that the densities of fresh water and salt water are:

density (salt water) = 1029 kg / m^3

density (fresh water) = 1000 kg / m^3

The amount of water (in mass) displaced by the barge should be equal in two waters.

mass displaced (salt water) = mass displaced (fresh water)

Since mass is also the product of density and volume, therefore:

<span>[density * volume]_salt water = [density * volume]_fresh water                 ---> 1</span>

 

First we calculate the amount of volume displaced in the harbour (salt water):

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Therefore the depth of the barge in the river is:

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<span>h = 0.72 m        (ANSWER)</span>

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