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Nadusha1986 [10]
3 years ago
7

Which of the following is a sign of a physical Change ?

Physics
2 answers:
guapka [62]3 years ago
7 0

C.) i believe because the change in shape is changing the physical appearance

galina1969 [7]3 years ago
5 0

<u>Answer:</u>

The correct answer option is C) A change in the shape of a substance.

<u>Explanation:</u>

Physical changes can be defined as the changes which affect the form of a chemical substance but not its chemical composition. These are the changes in which no bonds are broken or formed.

A change in the shape of a substance is a physical change because there is no change in composition of the substance chemically.

While all other options involve a change in chemical composition so they are not the examples of a physical change.

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Determine whether a moving tennis ball and a racket held by the player have the same momentum or different momentum. If differen
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Answer:

key points:1.momentum and impulse

2.condition for conservation of momentum and why

3.how to solve collision problems

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Explanation:

momentum is a vector

force of a tennis ball

for a top player,a tennis ball may leave the racket on the with a speed of 55m/s(about 120mi/h).if the ball has a mass of 0.060kg and is in contact with the racket for about 4ms(4×10)s.estimate the average force on the ball

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2 years ago
A minivan is tested for acceleration and braking. In the street-start acceleration test, the elapsed time is 8.6 s for a velocit
Varvara68 [4.7K]

The question is incomplete. Here is the complete question:

A minivan is tested for acceleration and braking. In the street-start acceleration test, the elapsed time is 8.6 s for a velocity increase from 10 km/h to 100 km/h. In the braking test, the distance traveled is 44 m during braking to a stop from 100 km/h. Assume constant values of acceleration and deceleration. Determine  

(a) the acceleration during the street-start test,  

(b) the deceleration during the braking test.

Answer:

(a) 37500 km/h²

(b) 113636.36 km/h²

Explanation:

part (a)

Because it is given that we can assume constant acceleration therefore we can use the following equation of motion:

<em>v = u + (a)(t) </em>

where <em>v </em>is final velocity, <em>u </em>is initial velocity, <em>a </em>is acceleration and <em>t </em>is time change

Given in the question:

v = 100km/h

u = 10 km/h

t = 8.6 sec (changing to hours)

t = 0.0024 hours (round off to 4 decimal places)

100 = 10 + (a x 0.0024)

Rearranging the equation to find value of a

a = (100 – 10) / 0.0024

a = 37500 km/h² (Answer)

part (b)

Now we can use the following equation to find deceleration

<em>2(a)(s) = v² – u²</em>

Where a is acceleration, s is distance travelled, v is final velocity and u is initial velocity

Given in the question

s = 44 m

changing to km

s = 0.044 km

v = 0 km/h (because it stops)

u = 100 km/h

2(a)(0.044) = (0)² – (100)²

0.088(a) = 0 - 10000  

a = - 10000/0.088

a = - 113636.36 km/h2  

The negative sign in the answer shows that it is deceleration

Therefore deceleration = 113636.36 km/h² (Answer)

6 0
3 years ago
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nirvana33 [79]

Answer:

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Image Formation Revisited

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The Mathematics of Lenses

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