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Montano1993 [528]
3 years ago
8

PLEASE HELP!! THANKS!! WILL MARK BRAINLIEST!!

Physics
1 answer:
GuDViN [60]3 years ago
4 0

Option C is the correct answer

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3 years ago
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Physically inactive (sitting down a lot during free time)<br>​
alekssr [168]
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The fins of a car radiator are painted black because black objects are good? ​
Tamiku [17]

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An astronaut named Speedo takes a trip to Sirius, which is located a distance of 8 lightyears from the Earth. If the spaceship m
Softa [21]

Answer:

<em>a. 10 years</em>

<em>b. 6 years</em>

<em>c. 12 years behind</em>

<em></em>

Explanation:

speed of light c =  3x10^{8} m/s

distance of sirius from earth = 8 lightyears = 8 x c x 60 x 60 x 24 x 365 = 252288000c meters

speed of spaceship = 0.8c

time taken to reach sirius = distance covered divided by speed

t = d/s = 252288000c/0.8c = 315360000 sec

<em>1 year = 60 x 60 x 24 x 365 sec = 31536000 sec</em>

315360000 sec = 315360000/31536000 = <em>10 yrs</em>

<em>the time as observed by Goslo will be shorter than the real time as measured within the ship due to relativistic effects. using the relativistic relation for time dilation we have</em>

t' = t\sqrt{1 - \frac{v^{2} }{c^{2} } }

since v = 0.8c

v/c = 0.8

where t' is the relativistic time as observed by Goslo,

t is the time within the ship

t' = 10 x \sqrt{1 - 0.8^{2}  }  = <em>6 yrs</em>

<em></em>

If speedo turns around immediately after reaching  sirius, his total distance will be 252288000c x 2 = 50457600c meter

time taken = 50457600c/0.8 = 630720000 sec = 20 yrs

time within the ship will be calculated from time dilation

t' = t\sqrt{1 - \frac{v^{2} }{c^{2} } }

t' = 20 x  \sqrt{1 - 0.8^{2}  }  = 378432000 sec = <em>12 years behind</em>

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3 years ago
What process is this?
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^they’re correct! it is weathering, i just took a test with that answer:)
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