Question

What is the equation of the line that passes through point (4,12) and has a y-intercept of -2?

Answer 1

The general formula of an equation is $y=mx+b$ we are told that the y-intercept is -2 as such we have the following so far $y=mx-2$
to calculate the slope we do the following:
$y=mx-2 \\ 12=m(4)-2 \\ 12=4m-2 \\ 14=4m \\ m= \frac{14}{4}$
therefore the equation is
$y= \frac{14}{4}x-2$