The mass (kg) of benzene is about 4470 kg
<h3>Further explanation</h3>
This problem is about Density.
Density is the ratio of mass to the volume of the object.

<em>ρ = density of object ( kg / m³ )</em>
<em>m = mass of object ( kg )</em>
<em>V = volume of object ( m³ )</em>
<u>Given:</u>
Diameter of Cylinder = d = 2.00 m
Radius of Cylinder = R = d/2 = 2.00/2 = 1.00 m
Length of Cylinder = L = 4.00 m
Liquid Depth = H = 0.85 m
Density of Benzene = ρ = 0.879 g/cm³ = 879 kg/m³
<u>Unknown:</u>
mass of benzene = m = ?
<u>Solution:</u>
This problem is about Liquid Volume in Partially Filled Horizontal Tanks
Firstly we will calculate the volume of Benzene by using following formula:


![V = [ R^2 \cos^{-1}(\frac{R - H}{R}) - (R - H)\sqrt {(2RH - H^2)} ] L](https://tex.z-dn.net/?f=V%20%3D%20%5B%20R%5E2%20%5Ccos%5E%7B-1%7D%28%5Cfrac%7BR%20-%20H%7D%7BR%7D%29%20-%20%28R%20-%20H%29%5Csqrt%20%7B%282RH%20-%20H%5E2%29%7D%20%5D%20L)
![V = [ 1^2 \cos^{-1}(\frac{1 - 0.85}{1}) - (1 - 0.85)\sqrt {(2(1)(0.85) - 0.85^2)} ] 4](https://tex.z-dn.net/?f=V%20%3D%20%5B%201%5E2%20%5Ccos%5E%7B-1%7D%28%5Cfrac%7B1%20-%200.85%7D%7B1%7D%29%20-%20%281%20-%200.85%29%5Csqrt%20%7B%282%281%29%280.85%29%20-%200.85%5E2%29%7D%20%5D%204)
![V = [ \cos^{-1} (0.15) - 0.15 \sqrt{ 0.9775} ] 4](https://tex.z-dn.net/?f=V%20%3D%20%5B%20%5Ccos%5E%7B-1%7D%20%280.15%29%20-%200.15%20%5Csqrt%7B%200.9775%7D%20%5D%204)




<h3>Learn more</h3>
<h3>Answer details</h3>
Grade: High School
Subject: Mathematics
Chapter: Density
Keywords: Temperature , Density , Iron , Sphere , Volume , Mass