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krok68 [10]
3 years ago
14

A diffraction grating with 270 lines per mm is used in an experiment to study the visible spectrum of a gas discharge tube. 1. A

t what angle from the beam axis will the fourth order peak occur if the tube emits light with wavelength of 665.0 nm?2. At what angle will the second order peak occur?
Physics
1 answer:
VikaD [51]3 years ago
6 0

Answer:

1) θ = 45.91°

2) θ = 21.04°

Explanation:

We are given;

Wavelength; λ = 665 nm = 6.65 × 10^(-7) m.

Distance between slits; d = 1mm/270 = 1/270 mm = (1/270) × 10^(-3) m

1) To find the angle, we will use the formula;

d sin θ = mλ

Where m is the order of peak which in this question is 4.

Thus, we have;

sin θ = mλ/d

sin θ = (4 × 6.65 × 10^(-7))/((1/270) × 10^(-3))

sin θ = 0.7183

θ = sin^(-1) 0.7183

θ = 45.91°

2) Similarly, d sin θ = mλ

Where m is the order of peak which in this question is 2. Thus;

sin θ = (2 × 6.65 × 10^(-7))/((1/270) × 10^(-3))

sin θ = 0.3591

θ = sin^(-1) 0.3591

θ = 21.04°

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nadezda [96]

1. 168.1 Hz

To find the apparent frequency heard by the driver in the car, we can use the formula for the Doppler effect:

f'=(\frac{v\pm v_o}{v\pm v_s})f

where

f is the original sound of the horn

v is the speed of sound

v_o is the velocity of the observer (the driver and the car), which is positive if the observer is moving towards the source and negative if it is moving away

v_s is the velocity of the sound source (the train), which is positive if the source is moving away from the observer and negative otherwise

In this problem we have, according to the sign convention used:

v = 343 m/s\\f = 164 Hz\\v_o = -15 m/s\\v_s = -23 m/s

Substituting, we find:

f'=(\frac{343-15}{343-23})(164)=168.1 Hz

2.  2.96\cdot 10^8 m/s

The speed of light can be calculated as

v=\frac{d}{t}

where

d is the distance travelled

t is the time taken

In this problem:

d=2\cdot 3.85\cdot 10^8 =7.7\cdot 10^8 m is the total distance travelled by the laser beam (twice the distance between the Earth and the Moon)

t = 2.60 s is the time taken

Substituting in the formula,

v=\frac{7.7\cdot 10^8 m}{2.60 s}=2.96\cdot 10^8 m/s

6 0
2 years ago
A 100-kg running back runs at 5 m/s into a stationary linebacker. It takes 0.5 s for the running back to be completely stopped.
Elza [17]

Answer:

1000 N

Explanation:

First, we need to find the deceleration of the running back, which is given by:

a=\frac{v-u}{t}

where

v = 0 is his final velocity

u = 5 m/s is his initial velocity

t = 0.5 s is the time taken

Substituting, we have

a=\frac{0-5 m/s}{0.5 s}=-10 m/s^2

And now we can calculate the force exerted on the running back, by using Newton's second law:

F=ma=(100 kg)(-10 m/s^2)=-1000 N

so, the magnitude of the force is 1000 N.

6 0
3 years ago
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2 years ago
Atoms that are bonded together to form a new material with new<br> properties and characteristics. .
mihalych1998 [28]

Answer:

Explanation:

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7 0
2 years ago
Blood plasma volume for adults is about 3.1 liters. It has a density of 1.020 gml. How many pounds of blood plasma are in your b
kari74 [83]

Answer:

mass is 6.97 pounds

Explanation:

given data

volume = 3.1 liters

density = 1.020 g/ml = 1.02 kg/l

to find out

How many pounds of blood plasma

solution

we know mass formula from density that is

density = mass / volume

so

mass = density × volume    ...............1

so put all value to get mass

mass = 1.02 × 3.1

mass = 3.162 kg

mass = 3.162  × 2.205 pounds

so mass is 6.97 pounds

6 0
3 years ago
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