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8090 [49]
3 years ago
12

Excretion of nitrogenous wastes in the form of uric acid has a _______ energy cost of production than excretion as urea. excreti

on or nitrogenous wastes as uric acid requires ______ water than excretion as urea
Chemistry
1 answer:
igomit [66]3 years ago
4 0
Protein increase into nervous
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True or false: All heterotrophs are omnivores.
RideAnS [48]

Answer:

False. They can be both omnivores and carnivores.

6 0
3 years ago
5. What concentration of acid must be added to change the pH of 1 mM phosphate buffer from 7.4 to 7.3 (pKas of the phosphate buf
mr_godi [17]

Explanation:

According to the Henderson-Hasselbalch equation, the relation between pH and pK_{a} is as follows.

               pH = pK_{a} + log \frac{base}{acid}

where,     pH = 7.4 and pK_{a} = 7.21

As here, we can use the pK_{a} nearest to the desired pH.

So,      7.4 = 7.21 + log \frac{base}{acid}

             0.19 = log \frac{base}{acid}

            \frac{base}{acid} = 1.55

1 mM phosphate buffer means [HPO_{4}] + [H_{2}PO_{4}] = 1 mM

Therefore, the two equations will be as follows.

           \frac{HPO_{4}}{H_{2}PO_{4}} = 1.55 ............. (1)

  [HPO_{4}] + [H_{2}PO_{4}] = 1 mM ........... (2)        

Now, putting the value of [HPO_{4}] from equation (1) into equation (2) as follows.

             1.55[H_{2}PO_{4}] + [tex][H_{2}PO_{4}] = 1 mM

                        2.55 [H_{2}PO_{4}] = 1 mM

                             [H_{2}PO_{4}] = 0.392 mM

Putting the value of [H_{2}PO_{4}] in equation (1) we get the following.

                     0.392 mM + [HPO_{4}] = 1 mM

                          [HPO_{4}] = (1 - 0.392) mM

                              [HPO_{4}] = 0.608 mM

Thus, we can conclude that concentration of the acid must be 0.608 mM.

7 0
3 years ago
If 3.89 × 1024 atoms of a noble gas is collected and it has a mass of of 848 grams, this element is most likely a. He b. Ne c. A
bearhunter [10]

Answer:

Xenon

Explanation:

Avogadro’s number represent the number of the constituent particles which are present in one mole of the substance. It is named after scientist Amedeo Avogadro and is denoted by N_0.

Avogadro constant:-

N_a=6.023\times 10^{23}

Let the molar mass of the element is x g/mol

So,

6.023\times 10^{23} atoms have a mass of x g

Also,

3.89\times 10^{24} atoms have a mass of \frac{x}{6.023\times 10^{23}}\times 3.89\times 10^{24} g

This mass is equal to 848 g

So,

\frac{x}{6.023\times 10^{23}}\times 3.89\times 10^{24}=848

x= 131.3 g/mol

This mass correspond to xenon.

3 0
3 years ago
How to differentiate between so3 and so4?​
makvit [3.9K]

Answer:

The difference between sulfate and sulfite is, Sulfate (SO4) has 1 atom of Sulphur and 4 atoms of Oxygen. sulfite (SO3) has 1 atom of sulfur and 3 atoms of Oxygen.

Explanation:

7 0
2 years ago
Balance each reaction and write its reaction quotient, Qc:(b) POCl₃(g) ⇄ PCl₃(g) + O₂(g)
Komok [63]

When we balance the given equation

      POCl₃(g) ⇄ PCl₃(g) + O₂(g)

We will get

      2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

Solution:

Balancing the given equation

      POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of O

      2POCl₃(g) ⇄ PCl₃(g) + O₂(g)

Balancing the number of P and Cl

      2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

We get the balanced equation

      2POCl₃(g) ⇄ 2PCl₃(g) + O₂(g)

The reaction quotient will be

     Qc = [product] / [reactant]

     Qc ​= [PCl₃(g) + O₂(g)] / [POCl₃(g) ]

To learn more click the given link

brainly.com/question/26227625

#SPJ4

4 0
1 year ago
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