True, if you would like an example look at Indian arrow heads or early architecture all use rocks.
Answer:
Symbol : S
molecule : S₈
Explanation:
The symbol of an element is just the representation with few alphabets (one or two) with no digit as we don't represent it for an atom or molecule. Just a symbol.
So for example
Symbol for Helium is He
Symbol for hydrogen is H
Symbol for sulfur is S
However the sulfur in nature exist as a molecule with eight atoms of sulfur.
Thus the elemental form of sulfur is an eight atomic molecule
The forms is represented as S₈.
Answer:
C15H24O
Explanation:
TO GET THE EMPIRICAL FORMULA, WE NEED TO KNOW THE MASSES AND CONSEQUENTLY THE NUMBER OF MOLES OF EACH OF THE INDIVIDUAL CONSTITUENT ELEMENTS.
FIRSTLY, WE CAN GET THE MASS OF THE CARBON FROM THAT OF THE CARBON IV OXIDE. WE NEED TO KNOW THE NUMBER OF MOLES OF CARBON IV OXIDE GIVEN OFF. THIS CAN BE CALCULATED BY DIVIVDING THE MASS BY THE MOLAR MASS OF CARBON IV OXIDE. THE MOLAR MASS OF CARBON IV OXIDE IS 44G/MOL
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HENCE, THE NUMBER OF MOLES OF CARBON IV OXIDE IS 4.122/44 WHICH EQUALS 0.094. SINCE THERE IS ONLY ONE ATOM OF CARBON IN CO2 THEN THEY HAVE EQUAL NUMBER OF MOLES AND THUS THE NUMBER OF MOLES OF CARBON IS 0.094. WE CAN THEN PROCEED TO CALCULATE THE MASS OF CO2 PRESENT. THIS CAN BE CALCULATED BY MULTIPLYING THE NUMBER OF MOLES BY THE ATOMIC MASS UNIT. THE ATOMIC MASS UNIT OF CARBON IS 12. HENCE, THE MASS OF CO2 PRESENT IS 12 * 0.094 = 1.128g</h3><h3>
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WE CAN NOW GET THE MASS OF THE HYDROGEN BY MULTIPLYING THE NUMBER OF MOLES OF WATER BY 2 AND ALSO ITS ATOMIC MASS UNIT</h3><h3>
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TO GET THE NUMBER OF MOLES OF WATER, WE SIMPLY DIVIDE THE MASS BY THE MOLAR MASS. THE MOLAR MASS OF WATER IS 18g/mol. The NUMBER OF MOLES IS THUS 1.350/18 = 0.075</h3><h3>
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THE NUMBER OF MOLES OF HYDROGEN IS TWICE THAT OF WATER SINCE IT CONTAINS 2 ATOMS PER MOLECULE OF WATER. ITS NUMBER OF MOLES IS THUS 0.075*2 = 0.15 MOLE</h3><h3>
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THE MASS OF HYDROGEN IS THUS 0.075 * 2 * 1 = 0.15g</h3><h3>
</h3><h3>WE CAN NOW FIND THE MASS OF OXYGEN BY SUBTRACTING THE MASSES OF HYDROGEN AND CARBON FROM THE TOTAL MASS.</h3><h3 /><h3>MASS OF OXYGEN = 1.376-0.15-1.128 = 0.098g</h3><h3 /><h3>THE NUMBER OF MOLES OF OXYGEN IS THUS 0.098/16 = 0.006125</h3><h3 /><h3>WE CAN NOW USE THE NUMBER OF MOLES TO OBTAIN THE EMPIRICAL FORMULA.</h3><h3 /><h3>WE DO THIS BY DIVIDING EACH BY THE SMALLEST NUMBER OF MOLES WHICH IS THAT OF THE OXYGEN.</h3><h3 /><h3>C = 0.094/0.006125 = 15</h3><h3>H = 0.15/0.006125 = 24</h3><h3>O = 1</h3><h3 /><h3>THE EMPIRICAL FORMULA IS THUS C15H24O</h3>
Answer:
128g
Explanation:
Given parameters:
Mass of carbon = 48g
Mass of carbon dioxide = 176g
Unknown:
Mass of oxygen that reacted = ?
Solution:
Every chemical reaction must obey the law of conservation of mass. It states that "in a chemical reaction, matter is neither created nor destroyed" .
So;
Mass of carbon + Mass of oxygen = Mass of carbon dioxide
Mass of oxygen = Mass of carbon dioxide - Mass of carbon
Mass of oxygen = 176 - 48 = 128g
