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castortr0y [4]
3 years ago
5

Which statement about atmospheric pressure is false? a) As air becomes thinner, its density decreases. b) The warmer the air, th

e lower the atmospheric pressure. c) Atmospheric pressure prevents water in lakes, rivers, and oceans from boiling away. d) With an increase in altitude, atmospheric pressure increases as well. e) Air actually has weight.
Physics
1 answer:
Ganezh [65]3 years ago
4 0

Answer:

The statement about atmospheric pressure that is false is <u><em>option d) With an increase in altitude, atmospheric pressure increases as well. </em></u>

Explanation:

Atmospheric pressure as the force exerted by atmospheric air on the earth's surface. The higher the height of the earth's surface with respect to sea level, which is the reference point, the lower the air pressure. In other words, atmospheric pressure decreases in altitude. This is because, the higher the height, the smaller the amount of air present for pressure. For example, on a mountain the amount of air in the highest part is less than that on a beach. This means that there is lower atmospheric pressure at the top.

Although it must be taken into account that the atmospheric pressure does not decrease proportionally in height, due to the high compressibility of the fluid (gas).

At sea level, which is the reference point, atmospheric pressure takes a value in different units of 1 atmosphere, 1013 millibars or 760 mm Hg.

So, <u><em>the statement about atmospheric pressure that is false is option d) With an increase in altitude, atmospheric pressure increases as well.</em></u> This is because, as mentioned, with an increase in altitude, the atmospheric pressure decreases.

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Answer:

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the initital kinetic energy is:

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and the final:

K_f=3*\frac{1}{2}*3.45*10^4kg*(1.67m/s)^2\\K_f=144kJ

The energy lost is given by:

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3 years ago
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Answer:

1.  E=5320.3J

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Explanation:

1. the thermal energy is given by the formula

E_T=\frac{3}{2}NK_BT=\frac{3}{2}(7.86*10^{23})(1.38*10^{-23}\frac{J}{K})(327.0K)=5320.3J

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2. Each degree of freedom contains one half of the total energy. Hence, the energy for one degree of freedom is

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E=\frac{1}{2}K_BT=2.25*10^{-21}J

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