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3 years ago

Which of the following diagrams correctly shows the electron configuration of Sulfur, with atomic number 16?

Physics

2 answers:

nika2105 [10]3 years ago

6 0

Answer:

Diagram C

Explanation:

We are given that Sulfur with atomic number 16.

We have to find that which diagram shows the electronic configuration of sulfur.

S=16

Its Diagram C

scoray [572]3 years ago

3 0

Diagram C because ..........

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3 years ago

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a particle is moving along a circular path having a radius of 4 in such that its position as a function of time is given by thet

ANTONII [103]

Answer:

Explanation:

Given

radius of circular path $r=4\ in.$

Position is given by

$\theta =\cos 2t---1$

Differentiate 1 to angular velocity we get

$\frac{\mathrm{d} \theta }{\mathrm{d} t}=\omega =-2\sin 2t----2$

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$\frac{\mathrm{d} \omega }{\mathrm{d} t}=-2^2\cos 2t ---3$

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$a_t=-4\cos 2t\times 4=-16\cos 2t$

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$a_r=(-2\sin 2t)^2\cdot 4$

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$a_{net}=\sqrt{a_r^2+a_t^2}$

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3 years ago

An uncrewed mission to the nearest star, Proxima Centauri, is launched from the Earth's surface as a projectile with an initial

Anna [14]

Answer:

42.96 km/s

Explanation:

From the conservation of Energy

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Mass gets cancelled

$-\frac{GM}{R}+\frac{1}{2}v_i^2=0+\frac{1}{2}v_f^2\\\Rightarrow -2\frac{GM}{R}+v_i^2=v_f^2\\\Rightarrow -v_e^2+v_i^2=v_f^2\\\Rightarrow v_f=\sqrt{v_i^2-v_e^2}$

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$v_i$ = Velocity of projectile = 44.4 km/s

$v_f=\sqrt{44.4^2-11.2^2}\\\Rightarrow v_f=42.96\ km/s$

The velocity of the spacecraft when it is more than halfway to the star is 42.96 km/s

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3 years ago

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Answer:

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