Answer:
Plate Tectonics
Explanation:
Plate tectonics is the scientific theory that the continents move around due to due plate tectonics and the movement of magma under the crust. This explains why some fossils of the same kind are found on other continents, and same goes for the Glacial Marks.
The two fields were physical quantities are used in motion calculations are length and mass with time.
The physical quantity in a field is referred as every point in a particular space time.
<h3>
How physical quantities are used in motion calculations?</h3>
If we consider an object, the physical property of the object is considered as physical quantity and to measure that object is known as units. The Physical quantity can be classified as elemental physical quantity and derived physical quantity. Length, mass, time, etc.. are elemental physical quantity, momentum, density, acceleration, etc... are derived physical quantity. Only for charge and temperature the physical quantity will be less than zero.
Length, mass and time are the physical quantities used in motion calculations.
Learn more about motion calculations,
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Answer:
![f2/f1 = \sqrt{2}](https://tex.z-dn.net/?f=%20f2%2Ff1%20%3D%20%5Csqrt%7B2%7D%20)
Explanation:
From frequency of oscillation
![f = 1/2pi *\sqrt{k/m}](https://tex.z-dn.net/?f=%20f%20%3D%201%2F2pi%20%2A%5Csqrt%7Bk%2Fm%7D%20)
Initially with the suspended string, the above equation is correct for the relation, hence
![f1 = 1/2pi *\sqrt{k/m}](https://tex.z-dn.net/?f=%20f1%20%3D%201%2F2pi%20%2A%5Csqrt%7Bk%2Fm%7D%20)
where k is force constant and m is the mass
When the spring is cut into half, by physics, the force constant will be doubled as they are inversely proportional
![f2 = 1/2pi *\sqrt{2k/m}](https://tex.z-dn.net/?f=%20f2%20%3D%201%2F2pi%20%2A%5Csqrt%7B2k%2Fm%7D%20)
Employing f2/ f1, we have
![f2/f1 = \sqrt{2}](https://tex.z-dn.net/?f=%20f2%2Ff1%20%3D%20%5Csqrt%7B2%7D%20)
Answer:
x=?
dt=?
vi=23m/s
vf=0m/s (it stops)
d=0.25m/s^2
time =
vf=vi+d: 0=23m/s+(0.25m/s^2)t
t=92s
displacement=
vf^2=vi^2+2a(dx)
23^2=0^2+2(0.25m/s^2)x =-1058m
Explanation:
you can find time from vf = vi + a(Dt): 0 = 23 m/s + (0.25 m/s/s)t so t = 92 s and you can find the displacement from vf2 = vi2 + 2a(Dx) and find the answer in one step: 232 = 02 + 2(0.25 m/s/s)x so x = -1058 m